okay guys Im stuck and i don't know what to do after this step. here is the problem: 12b^2-29b+15 me: 3(b^2+20b)(9b+5) It has to be factored out by grouping why do I feel it is not complete?

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okay guys Im stuck and i don't know what to do after this step. here is the problem: 12b^2-29b+15 me: 3(b^2+20b)(9b+5) It has to be factored out by grouping why do I feel it is not complete?

Mathematics
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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are you a smart jokester?

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\[12b^2-29b+15\]\[(4b-3)(3b-5)\]This is what you should have done. I'm not sure how you got your answer. This one shouldn't be factored by grouping as it only has 3 terms.
thanks X I appreciate your input.
no prob
If you'll notice, if you re-simplify your answer, you won't get the original expression. This is one way to check yourself.
Thanks X I am going to do that next time to be sure:)

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