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anonymous

  • 4 years ago

okay guys Im stuck and i don't know what to do after this step. here is the problem: 12b^2-29b+15 me: 3(b^2+20b)(9b+5) It has to be factored out by grouping why do I feel it is not complete?

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  1. anonymous
    • 4 years ago
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    Call ghost busters

  2. anonymous
    • 4 years ago
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    Oh mrs happy you got jokes I like a jokester

  3. anonymous
    • 4 years ago
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    are you a smart jokester?

  4. Xishem
    • 4 years ago
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    \[12b^2-29b+15\]\[(4b-3)(3b-5)\]This is what you should have done. I'm not sure how you got your answer. This one shouldn't be factored by grouping as it only has 3 terms.

  5. anonymous
    • 4 years ago
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    thanks X I appreciate your input.

  6. anonymous
    • 4 years ago
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    no prob

  7. Xishem
    • 4 years ago
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    If you'll notice, if you re-simplify your answer, you won't get the original expression. This is one way to check yourself.

  8. anonymous
    • 4 years ago
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    Thanks X I am going to do that next time to be sure:)

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spraguer (Moderator)
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