anonymous
  • anonymous
1. A spring has a natural length of 10 in. An 800-lb force stretches the spring to 14 in. (a) Find the force constant. (b) How much work is done in stretching the spring from 10 in. to 12 in.? (c) How far beyond its natural length will a 1600-lb force stretch the spring
Mathematics
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anonymous
  • anonymous
1. A spring has a natural length of 10 in. An 800-lb force stretches the spring to 14 in. (a) Find the force constant. (b) How much work is done in stretching the spring from 10 in. to 12 in.? (c) How far beyond its natural length will a 1600-lb force stretch the spring
Mathematics
chestercat
  • chestercat
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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anonymous
  • anonymous
Try clicking this site http://answers.yahoo.com/question/index?qid=20080314130027AAOwPZH
anonymous
  • anonymous
Wouldn't I need to integrate since it doesn't start from 0?
UnkleRhaukus
  • UnkleRhaukus
yeah integrate the force time displacement to get the total work \[W_{0 \rightarrow x} =\int_0^xFdx\]

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anonymous
  • anonymous
No I mean would I integrate to get the constant K?
anonymous
  • anonymous
or would it just be 800=4k

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