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anonymous
 4 years ago
A solid candy jawbreaker is cut in half. If its diameter is 4 cm, what is the surface area of a half piece? please show me the steps.
anonymous
 4 years ago
A solid candy jawbreaker is cut in half. If its diameter is 4 cm, what is the surface area of a half piece? please show me the steps.

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anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0dw:1328844308091:dw

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0i am getting 8 pi .is it right

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0i think it should be 48pi

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0oh hell, no.... i thought radius was 4, not diameter... sec

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0answer is 12 pi.I don't know how

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.02A = 4pi*r^2 2A = 4pi*(2)^2 2A = 16pi A = 8pi I set it equal to 2A because we want half the surface area, I found the full SA then divided by 2.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0the surface area on the outside is 8pi, you're correct, but you need to add the surface are where the cut was made (basically the area of a circle radius 4

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0please can you explain

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Ahhh yes I forgot about the inside cut. I assumed a hollow sphere. :O stupid mee

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0It's the surface area of half a sphere plus the surface area of the circle... \[\frac{4πr^2}{2}+\pi r^2=2 \pi r^2+\pi r ^2=3 \pi r^2= 3 \pi (2cm)^2=12 \pi\ cm\]
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