A community for students.
Here's the question you clicked on:
 0 viewing
sammy12
 4 years ago
A solid candy jawbreaker is cut in half. If its diameter is 4 cm, what is the surface area of a half piece? please show me the steps.
sammy12
 4 years ago
A solid candy jawbreaker is cut in half. If its diameter is 4 cm, what is the surface area of a half piece? please show me the steps.

This Question is Closed

sammy12
 4 years ago
Best ResponseYou've already chosen the best response.0i am getting 8 pi .is it right

Tonik
 4 years ago
Best ResponseYou've already chosen the best response.1i think it should be 48pi

Tonik
 4 years ago
Best ResponseYou've already chosen the best response.1oh hell, no.... i thought radius was 4, not diameter... sec

sammy12
 4 years ago
Best ResponseYou've already chosen the best response.0answer is 12 pi.I don't know how

funinabox
 4 years ago
Best ResponseYou've already chosen the best response.12A = 4pi*r^2 2A = 4pi*(2)^2 2A = 16pi A = 8pi I set it equal to 2A because we want half the surface area, I found the full SA then divided by 2.

Tonik
 4 years ago
Best ResponseYou've already chosen the best response.1the surface area on the outside is 8pi, you're correct, but you need to add the surface are where the cut was made (basically the area of a circle radius 4

funinabox
 4 years ago
Best ResponseYou've already chosen the best response.1Ahhh yes I forgot about the inside cut. I assumed a hollow sphere. :O stupid mee

Xishem
 4 years ago
Best ResponseYou've already chosen the best response.0It's the surface area of half a sphere plus the surface area of the circle... \[\frac{4πr^2}{2}+\pi r^2=2 \pi r^2+\pi r ^2=3 \pi r^2= 3 \pi (2cm)^2=12 \pi\ cm\]
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.