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sammy12

  • 2 years ago

A solid candy jawbreaker is cut in half. If its diameter is 4 cm, what is the surface area of a half piece? please show me the steps.

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  1. beth1127
    • 2 years ago
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    |dw:1328844308091:dw|

  2. sammy12
    • 2 years ago
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    i am getting 8 pi .is it right

  3. Tonik
    • 2 years ago
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    i think it should be 48pi

  4. Tonik
    • 2 years ago
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    oh hell, no.... i thought radius was 4, not diameter... sec

  5. sammy12
    • 2 years ago
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    answer is 12 pi.I don't know how

  6. funinabox
    • 2 years ago
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    2A = 4pi*r^2 2A = 4pi*(2)^2 2A = 16pi A = 8pi I set it equal to 2A because we want half the surface area, I found the full SA then divided by 2.

  7. sammy12
    • 2 years ago
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    i am getting 8 pi

  8. Tonik
    • 2 years ago
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    the surface area on the outside is 8pi, you're correct, but you need to add the surface are where the cut was made (basically the area of a circle radius 4

  9. Tonik
    • 2 years ago
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    ugh, radius 2

  10. Tonik
    • 2 years ago
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    so its 12pi

  11. sammy12
    • 2 years ago
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    please can you explain

  12. funinabox
    • 2 years ago
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    Ahhh yes I forgot about the inside cut. I assumed a hollow sphere. :O stupid mee

  13. Xishem
    • 2 years ago
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    It's the surface area of half a sphere plus the surface area of the circle... \[\frac{4πr^2}{2}+\pi r^2=2 \pi r^2+\pi r ^2=3 \pi r^2= 3 \pi (2cm)^2=12 \pi\ cm\]

  14. Xishem
    • 2 years ago
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    *\[12\pi\ cm^2\]

  15. sammy12
    • 2 years ago
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    Thanks

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