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anonymous
 4 years ago
Simplify, if possible.
(b^2/b^3)^2
anonymous
 4 years ago
Simplify, if possible. (b^2/b^3)^2

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anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0any number raised to a negative exponent can be reciprocated, for example: x^1 = 1/x and if you have x^1/x^2, just add the exponents like 1/x^1+2 = 1/x^3 and if you have (1/x^2)^2, just multiply that second exponent through (it needs to be distributed. it'd be 1/x^4.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0\[\left(\begin{matrix}b ^{2} \\b ^{3}\end{matrix}\right)^{2}=\left( b ^{23} \right)^{2}=\left( b ^{5} \right)^{2}=b ^{5\times2}=b ^{10}\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0I'm sorry, I squared it by mistake. It should be, 1/(b^10)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0\[\left(\begin{matrix}a ^{m} \\a ^{n}\end{matrix}\right)=a ^{m n}\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0\[\left( a ^{m} \right)^{n}=a ^{m.n}\]
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