So in class we're reviewing First Prinicipals (which is the only sad part about Calculus), and I can't seem to get this equation on it. I can get it using the power rule, but it's strange for FP.
Find the slope of the tangent for the function y=(x-2)^1/2 at the point (3,1)

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\[y = \sqrt{x-2}\] @ (3,1)

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