A triangle has vertices at (2, 3), (½ , –2), and (– 3, 2). What is the area of the triangle? please show me the steps

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A triangle has vertices at (2, 3), (½ , –2), and (– 3, 2). What is the area of the triangle? please show me the steps

Mathematics
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no
Please can you explain
Just use the formula 1/2(x1 y2 + x2 y3 + x3y1- x2y1-x3y2-x1y3)

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Otherwise do you know distance formula?
And how to calculate distance of a point from a line?
yes .I do
Ah ok. So lets use co ordinate geometry . Can you tell me equation of line passing through (1/2,-2) and (3,-2)?
And (-3,2) sorry
chealsea rules.
of course it does(but thats irrevelant to finding area of a triangle. :P)
y=-8/7x-10/7
Ok I'll assume you did that correctly. Now find distance of (2,3) from this line.
please can you explain me how to
Ok Suppose i have a line ax+by+c=0. And a point h,k. Then disatnce of point from this line would be (ah+bk+c)/sqrt(a^2+b^2). If you get negative value just make it positive by removing minus sign.
understood?
no. I didn't
You did not understand the formula? Damn. Ok In your case the line is 7y+8x+10=0. And the point is 2,3. Si a=7,b=8,c=10. h=2,k=3. Using the formula you get (7*2+8*3+10)/sqrt(64+49)=48/sqrt(113).
Now is it a little bit clearer?
yes
good, now find distance AB.
Then just do 1/2 * AB * 48/sqrt(113).
answer is 47/4. Thanks for helping

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