anonymous
  • anonymous
use the pythagorean theorem to answer the following question: (picture)
Mathematics
schrodinger
  • schrodinger
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anonymous
  • anonymous
|dw:1328847511104:dw|
anonymous
  • anonymous
\[c^{2}=a^{2}+b^{2}\]
anonymous
  • anonymous
i got rad 3 but its not right

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anonymous
  • anonymous
X^2+X^2=c^2 2X^2=C^2 2x^2=36 2x=6 x=3
anonymous
  • anonymous
6 = (2x^2)^(0.5) x = 4.24
anonymous
  • anonymous
can someone simply write it out?
anonymous
  • anonymous
x^2+X^2=36 x+x=6 2x=6 x=3
anonymous
  • anonymous
as both side lengths = x, both angles must be the same length. 2x^2=c^2 2x^2=36 2x=6 x=3 "i got rad 3 but its not right" You probably didn't square 6. If you don't, then: 2x^2=6 x^2 = 3 x=sqrt(3) what you got
anonymous
  • anonymous
|dw:1328847676206:dw|
anonymous
  • anonymous
right! I forgot to do 6*6 Thanks everyone!
anonymous
  • anonymous
What's the right answer again?
anonymous
  • anonymous
And to write out the full formula: a^2 + b^2 = c^2 however, a and b are the same length, so... x^2 + x^2 = c^2 2x^2 = c^2 2x^2 =36 x^2 = 18 x = sqrt(18) <---- that's the actual answer sometimes helps to write out the full thing lol
anonymous
  • anonymous
So I was right? I actually doubted myself for a moment there.....
anonymous
  • anonymous
except for where you said it is = 4.24. That's an approximation.

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