what is the slope (-3,0) horizontal and (0,5) parallel

- anonymous

what is the slope (-3,0) horizontal and (0,5) parallel

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- anonymous

the slope for (-3,0) (0,5)

- KatrinaKaif

Do you know how to get to the slope?

- anonymous

no not really

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## More answers

- KatrinaKaif

Can you tell me the slope formula? it would be a start

- anonymous

(x1,y1)...(x2,y2)
m = (y2 - y1) / (x2 - x1)

- anonymous

where (x1,y1)...(x2,y2) are ordered pairs like (2,3) or (0,4)

- anonymous

y2-y1/x2-x1

- anonymous

ok are you looking for the slope of the parallel line that contains (0,5)?

- anonymous

but t sure how to work it

- anonymous

that was really bad timing on my answer >_>

- KatrinaKaif

The points given are:
(-3,0) = (x1,y1)
and
( 0,5) = (x2,y2)
Plug these values in the equation you gave me.

- anonymous

yes but the way he has writtin it is that horizontal line that contains (3,0)

- anonymous

parallel line contains (5,0)

- KatrinaKaif

Can you clarify your question Pinkwhispers80? It seems to have a bit of a wording problem.

- anonymous

that would mean both lines have no slope

- anonymous

because they would both be horizontal

- KatrinaKaif

When two lines are parallel, they simply would not have a slope Whispers

- anonymous

I have a graph that contains a line with points being (-3,0) and (0,5) I need to find the slope but Im not sure how

- KatrinaKaif

I believe Chris is headed the right direction

- KatrinaKaif

Well then, you can use what I had previously posted.

- anonymous

do are you given a horizontal line and parallel line or both points on one line?

- anonymous

just weird to use the words horizontal and parallel because that says they are two sperate lines

- anonymous

sorry I didnt know that its one line

- anonymous

k then y2-y1/x2-x1

- KatrinaKaif

Can you draw it out for us with the drawing tool located below?

- anonymous

5-0/0-3
5/-3
-5/3

- anonymous

your slope would be -5/3

- KatrinaKaif

^Correct

- anonymous

|dw:1328848542441:dw|

- KatrinaKaif

Then use the explanations by Chris and me above. =)

- anonymous

Thanks yall!!! Im trying to figure all this algebra stuff out.

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