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the slope for (-3,0) (0,5)
Do you know how to get to the slope?
no not really
Can you tell me the slope formula? it would be a start
(x1,y1)...(x2,y2) m = (y2 - y1) / (x2 - x1)
where (x1,y1)...(x2,y2) are ordered pairs like (2,3) or (0,4)
ok are you looking for the slope of the parallel line that contains (0,5)?
but t sure how to work it
that was really bad timing on my answer >_>
The points given are: (-3,0) = (x1,y1) and ( 0,5) = (x2,y2) Plug these values in the equation you gave me.
yes but the way he has writtin it is that horizontal line that contains (3,0)
parallel line contains (5,0)
Can you clarify your question Pinkwhispers80? It seems to have a bit of a wording problem.
that would mean both lines have no slope
because they would both be horizontal
When two lines are parallel, they simply would not have a slope Whispers
I have a graph that contains a line with points being (-3,0) and (0,5) I need to find the slope but Im not sure how
I believe Chris is headed the right direction
Well then, you can use what I had previously posted.
do are you given a horizontal line and parallel line or both points on one line?
just weird to use the words horizontal and parallel because that says they are two sperate lines
sorry I didnt know that its one line
k then y2-y1/x2-x1
Can you draw it out for us with the drawing tool located below?
5-0/0-3 5/-3 -5/3
your slope would be -5/3
Then use the explanations by Chris and me above. =)
Thanks yall!!! Im trying to figure all this algebra stuff out.