## pinkwhispers80 3 years ago what is the slope (-3,0) horizontal and (0,5) parallel

1. pinkwhispers80

the slope for (-3,0) (0,5)

2. KatrinaKaif

Do you know how to get to the slope?

3. pinkwhispers80

no not really

4. KatrinaKaif

Can you tell me the slope formula? it would be a start

5. funinabox

(x1,y1)...(x2,y2) m = (y2 - y1) / (x2 - x1)

6. funinabox

where (x1,y1)...(x2,y2) are ordered pairs like (2,3) or (0,4)

7. pinkwhispers80

y2-y1/x2-x1

8. ChrisV

ok are you looking for the slope of the parallel line that contains (0,5)?

9. pinkwhispers80

but t sure how to work it

10. funinabox

11. KatrinaKaif

The points given are: (-3,0) = (x1,y1) and ( 0,5) = (x2,y2) Plug these values in the equation you gave me.

12. ChrisV

yes but the way he has writtin it is that horizontal line that contains (3,0)

13. ChrisV

parallel line contains (5,0)

14. KatrinaKaif

Can you clarify your question Pinkwhispers80? It seems to have a bit of a wording problem.

15. ChrisV

that would mean both lines have no slope

16. ChrisV

because they would both be horizontal

17. KatrinaKaif

When two lines are parallel, they simply would not have a slope Whispers

18. pinkwhispers80

I have a graph that contains a line with points being (-3,0) and (0,5) I need to find the slope but Im not sure how

19. KatrinaKaif

I believe Chris is headed the right direction

20. KatrinaKaif

Well then, you can use what I had previously posted.

21. ChrisV

do are you given a horizontal line and parallel line or both points on one line?

22. ChrisV

just weird to use the words horizontal and parallel because that says they are two sperate lines

23. pinkwhispers80

sorry I didnt know that its one line

24. ChrisV

k then y2-y1/x2-x1

25. KatrinaKaif

Can you draw it out for us with the drawing tool located below?

26. ChrisV

5-0/0-3 5/-3 -5/3

27. ChrisV

28. KatrinaKaif

^Correct

29. pinkwhispers80

|dw:1328848542441:dw|

30. KatrinaKaif

Then use the explanations by Chris and me above. =)

31. pinkwhispers80

Thanks yall!!! Im trying to figure all this algebra stuff out.