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the slope for (-3,0) (0,5)

Do you know how to get to the slope?

no not really

Can you tell me the slope formula? it would be a start

(x1,y1)...(x2,y2)
m = (y2 - y1) / (x2 - x1)

where (x1,y1)...(x2,y2) are ordered pairs like (2,3) or (0,4)

y2-y1/x2-x1

ok are you looking for the slope of the parallel line that contains (0,5)?

but t sure how to work it

that was really bad timing on my answer >_>

yes but the way he has writtin it is that horizontal line that contains (3,0)

parallel line contains (5,0)

Can you clarify your question Pinkwhispers80? It seems to have a bit of a wording problem.

that would mean both lines have no slope

because they would both be horizontal

When two lines are parallel, they simply would not have a slope Whispers

I believe Chris is headed the right direction

Well then, you can use what I had previously posted.

do are you given a horizontal line and parallel line or both points on one line?

just weird to use the words horizontal and parallel because that says they are two sperate lines

sorry I didnt know that its one line

k then y2-y1/x2-x1

Can you draw it out for us with the drawing tool located below?

5-0/0-3
5/-3
-5/3

your slope would be -5/3

^Correct

|dw:1328848542441:dw|

Then use the explanations by Chris and me above. =)

Thanks yall!!! Im trying to figure all this algebra stuff out.