anonymous
  • anonymous
3x + 2y= 2 4x + y= -4
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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anonymous
  • anonymous
multiply second equation by 2
anonymous
  • anonymous
3x+2y=2 8x+2y=-8
anonymous
  • anonymous
subtract second from first

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anonymous
  • anonymous
-5x=10 x=-2
anonymous
  • anonymous
y=4
anonymous
  • anonymous
um you did that wrong
anonymous
  • anonymous
let me show you the correct way its called elimination method
anonymous
  • anonymous
oh where's my mistake? i'm not perfect sorry.
anonymous
  • anonymous
3x + 2y= 2 (4x + y= -4)-2
anonymous
  • anonymous
3x + 2y= 2 4x + y= -4 --------- y = -4x - 4 3x + 2(-4x - 4) = 2 3x -8x - 8 = 2 -5x = 10 x = -2 3(-2) + 2y = 2 -6 + 2y = 2 2y = 8 y = 4 (-2,4)
anonymous
  • anonymous
3x+2y=2 -8x-2y=8
anonymous
  • anonymous
-5x=10 x=-2
anonymous
  • anonymous
substitution >>> elimination
anonymous
  • anonymous
you want the y's to cancel
anonymous
  • anonymous
so its times -2 not 2
anonymous
  • anonymous
are you not seeing how we got the same answer. Chris?
anonymous
  • anonymous
the difference is I subtracted the equations. I didn't add them.
anonymous
  • anonymous
slet me show you substitution then
anonymous
  • anonymous
You can do either. You might want to properly educate yourself on the topic before you start calling people out.
anonymous
  • anonymous
3x + 2y= 2 4x + y= -4
anonymous
  • anonymous
wait5 a sec
anonymous
  • anonymous
ill show you
anonymous
  • anonymous
i already did the substitution method juss sayin'
anonymous
  • anonymous
for substitution i would solve one equation for y
anonymous
  • anonymous
hah heated.
anonymous
  • anonymous
before you finish. my answer was x = -2 and y = 4 as shown above. So you are going to tell me that is incorrect?
anonymous
  • anonymous
4x + y= -4 y=-4x-4
anonymous
  • anonymous
substitute that for y in the other equation
anonymous
  • anonymous
4 = -4x-4 8 = -4x x=-2
anonymous
  • anonymous
Chris. just stop.
anonymous
  • anonymous
3x + 2(-4x-4)= 2 3x-8x-8=2 -5x=10 x=-2
anonymous
  • anonymous
Lol
anonymous
  • anonymous
thank you for again proving my point
anonymous
  • anonymous
thats substitution
anonymous
  • anonymous
there was nothing wrong with the elimination method I did. get over it.
anonymous
  • anonymous
you multiplies by 2 instead of -2
anonymous
  • anonymous
it was completely wrong
anonymous
  • anonymous
+2y and +2y do not eliminate
anonymous
  • anonymous
that would give him 4y
anonymous
  • anonymous
I am not saying you were trying to do it wrong, you just made a mistake
radar
  • radar
ChrisV you can always expand your horizons. Yes you can multiply by -2 then add, But you can just as easily and correctly multiply by +2 and then subtract. The fact that you can eliminate by both adding or subtracting is something you should put in your "solving" tool box.
anonymous
  • anonymous
3x+2y=2 8x+2y=-8 11x+4y=-6 that in know way is right
anonymous
  • anonymous
you can not multiply by 2 and get the right answer there
anonymous
  • anonymous
if you can my friend you have invented a new form of the elimination method
anonymous
  • anonymous
please add it to my precal book so i can inform the aurhors
anonymous
  • anonymous
you have to multiply bu -2 not 2
anonymous
  • anonymous
3x+2y=2 -8x-2y=8 -5x=10 x=-2
radar
  • radar
You are missing the point: 3x+2y=2 -(8x+2y=-8) ------------ -5x = 10 x=-2
anonymous
  • anonymous
why not call it the subtraction method then? The point is to multiply by a value that eliminates a variable
anonymous
  • anonymous
Just tryinying to sho the simplest way i guess, but yes that comes out correct too
anonymous
  • anonymous
show
anonymous
  • anonymous
anyways lets do something else lol, nothing more to argue about here. Just gonna disagree anyways
radar
  • radar
Yes that is true, and you may eliminate it either by subtracting or adding depending on your choice of the sign of your multiplier. I am not saying you are wrong and if you wish to restrict your mode of operation to always adding, then have at it.
anonymous
  • anonymous
not adding its called multiplication
anonymous
  • anonymous
lol Chris, maybe when you further your actual understanding of what it means to execute the elimination method then talk to me. Go ask any knowledgeable math teacher or professor you have ever had. I don't appreciate being told that I'm wrong when clearly, I am not. I'm not at all saying what you did was wrong but the fact that you have the inability to realize that the elimination method has multiple execution techniques and then accusing EVERYONE else of being wrong is just disrespectful. I'm sure you are a smart guy but you need to expand your horizon. I have been doing a lot of math for a very long time now. Good luck in the future.

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