anonymous
  • anonymous
elimination method 7r-6s=36 6r+7s=43 ordered pair solution (-13,6) is this right??
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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Hero
  • Hero
7r-6s=36 6r+7s=43 r = (36 + 6s)/7 r = (43-7s)/6 r = r 6(36 + 6s) = 7(43 - 7s) 216 + 36s = 301 - 49s 301 - 216 = 85s 85 = 85s 85/85 = s 1 = s
Hero
  • Hero
r = 6
anonymous
  • anonymous
(7r-6s=36)-6 (6r-7s=43)7 -42r+36s=-216 42r-49s=301 13s=85

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More answers

anonymous
  • anonymous
s=85/13
Hero
  • Hero
Chris, (r,s) = (6,1) is the solution
anonymous
  • anonymous
-85/13 oops
anonymous
  • anonymous
ok how is what you did elimination method?
Hero
  • Hero
If you want me to prove it to you, I will
Hero
  • Hero
Because I eliminated r variable, then solved for s
Hero
  • Hero
It's just not elimination method you're used to. Besides, my methods get the correct answer. I can't really speak for the elimination methods you're used to.
anonymous
  • anonymous
please do i have never seen your way
Hero
  • Hero
I invented my way, that's why. If you use x and y as variables you'll see why.
anonymous
  • anonymous
always inte
Hero
  • Hero
I invented a plethora of approaches to math that make much more sense than methods taught in school. Some of which are pretty silly and potentially confusing.
Hero
  • Hero
You can prove it to yourself by plugging in r = 6 and s = 1 back into the original equations
anonymous
  • anonymous
Chris Chris Chris..
anonymous
  • anonymous
lol i asked him to teach me? what?
anonymous
  • anonymous
i am sure i made a mistake somewhere but i was interested in his method
Hero
  • Hero
The method I use, you've been taught it already.
Hero
  • Hero
y = mx+b If you have an equation with x and y on the same side, and you want to isolate y, say, for graphing reasons, you can do that. In this case, I isolated r, which would be y. I do this so that it's easier to solve systems of equations, also I can graph the equations I isolated on a graph to check them. So I'm doing two thing by using my method. I'm providing a way to check my answer graphically, and I'm finding an easier, simplier way to solve the more difficult systems of equation problems.
anonymous
  • anonymous
oh i already looked at what you did but to me its a lot like the susbstitution methos instead of the elimination method asked in the question
Hero
  • Hero
7y-6x=36 6y+7x=43 y = (36 + 6x)/7 <---I graph this to check y = (43-7x)/6 <---and this too y = y 6(36 + 6x) = 7(43 - 7x) 216 + 36x = 301 - 49x 301 - 216 = 85x 85 = 85x 85/85 = x 1 = x 6 = y
anonymous
  • anonymous
you must realize that some instructors would want to see that problem done by instruction instead of substituting for r
anonymous
  • anonymous
but im not arguing, just making an observation
Hero
  • Hero
I would argue that I did eliminate one variable while solving.
anonymous
  • anonymous
what you did was solve each equation for r then set them equal
Hero
  • Hero
Either way, no one has yet to post the solution you're looking for.
Hero
  • Hero
I figure that maybe you would but instead you want to argue with me.
anonymous
  • anonymous
well im justsaying what you did is almost the exact definition of the substitution method
Hero
  • Hero
Chris, everyone is waiting for you to post the "correct" solution.
anonymous
  • anonymous
well ok ill show you
Hero
  • Hero
I posted my solution because I don't care much for the elimination method as you know it.
anonymous
  • anonymous
but im not arguing
Hero
  • Hero
Whatever you say man :P
anonymous
  • anonymous
i unsderstand that, and if the question didnt ask for a specific method i would agree with you
anonymous
  • anonymous
im not trying to argue with you at all
anonymous
  • anonymous
(7r-6s=36)-6 (6r-7s=43)7 -42r+36s=-216 42r+49s=301 85s=85 s=1
Hero
  • Hero
I posted a solution since no one had posted one yet. And by technicality, I did indeed eliminate r variable by substitution.
anonymous
  • anonymous
that would be elimination method
anonymous
  • anonymous
same answer just different method
Hero
  • Hero
Well, it's about time...only took about a whole hour for someone to do it.
anonymous
  • anonymous
if they had asked them to do it susbstitution method, you answer is absolutely correct
anonymous
  • anonymous
there is just two different methods
Hero
  • Hero
If it has to take an hour to post the solution, I'd rather stick with my methods...
anonymous
  • anonymous
well just realize there are two methods and when it asks you do do it that way for college per say, then the other method would be wrong
anonymous
  • anonymous
even though the answer is the same
Hero
  • Hero
I'm just happy the correct solution is finally posted. I just posted my solution for fun.
anonymous
  • anonymous
heh no problem man, just do not want you to think I am arguing
Hero
  • Hero
I know, you're just trying to get your point across while I'm trying to get mine across. No one in their right minds would consider that arguing :P
anonymous
  • anonymous
lol i call it debating
anonymous
  • anonymous
one of us will come up with the right answer eventually
Hero
  • Hero
debating = formal argument
anonymous
  • anonymous
it sounds nicer though
Hero
  • Hero
This must have been how it was like when Leibnitz and Newton was arguing over who invented Calculus
anonymous
  • anonymous
lol
Hero
  • Hero
Good night Chris...
anonymous
  • anonymous
night

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