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anonymous

  • 4 years ago

Can someone break down the 5 rules of logarithms for me?

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  1. anonymous
    • 4 years ago
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    \[\log{a}+\log b=\log(ab)\] \[\log a- logb=\log(a/b)\] \[m \log a=\log a^m\] \[\frac{\log a}{\log b}=\log_{b}a\] \[x^{\log_xa}\]

  2. perl
    • 4 years ago
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    you need a base c for your change of basis formula log_b a = log_c a / log_c b

  3. lgbasallote
    • 4 years ago
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    ^actually...NotSObright is right...:)

  4. perl
    • 4 years ago
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    i didnt say its wrong, but it can be another base, than the default base

  5. anonymous
    • 4 years ago
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    i only remember power/ quotient/ and power rules was there more to it?

  6. anonymous
    • 4 years ago
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    product

  7. perl
    • 4 years ago
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    see above

  8. anonymous
    • 4 years ago
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    In all the above formulas is for all bases ob default valid until you use that same base

  9. perl
    • 4 years ago
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    all bases valid , yes

  10. anonymous
    • 4 years ago
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    so rules only apply or can be different under certain circumstances?

  11. lgbasallote
    • 4 years ago
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    depends on the situation

  12. anonymous
    • 4 years ago
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    You learn through practice

  13. perl
    • 4 years ago
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    ok here are some examples log 2 + log 3 = log (2*3). ln (2/3) = ln 2 - ln 3

  14. perl
    • 4 years ago
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    log 2 + ln 3 does not combine, because they are different bases

  15. perl
    • 4 years ago
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    log 2^3 = 3* log 2 , see if you can find which rule I used

  16. perl
    • 4 years ago
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    so log 8 = log (2^3) = 3 log 2 so log 8 = 3 log 2

  17. anonymous
    • 4 years ago
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    ok it cleared it up a bit ty m8

  18. anonymous
    • 4 years ago
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    rule of power right?

  19. Directrix
    • 4 years ago
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    Summary of log laws and demo problems at the link ---> http://www.themathpage.com/aprecalc/logarithms.htm#laws

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