anonymous
  • anonymous
a car is traveling in a straight line and decelerating at a constant rate. after 3.2 seconds it has traveled 88m and slowed to a speed of 27 m/s what is the initial speed i got 52 m/s
Mathematics
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anonymous
  • anonymous
a car is traveling in a straight line and decelerating at a constant rate. after 3.2 seconds it has traveled 88m and slowed to a speed of 27 m/s what is the initial speed i got 52 m/s
Mathematics
chestercat
  • chestercat
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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anonymous
  • anonymous
\[v^2-2as=u^2\]
perl
  • perl
what does s and u stand for?
anonymous
  • anonymous
Put \[a=\frac{v-u}{t}\]

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anonymous
  • anonymous
s distance u initial velocity
anonymous
  • anonymous
and the plug a back into the equation that is what i did but im not sure if my math is right
anonymous
  • anonymous
other people had like 97m/s which didnt make sense to me
perl
  • perl
v is final velocity, u is initial velocity
anonymous
  • anonymous
Better use \[s=ut+\frac{1}{2}at^2\]
perl
  • perl
so youre using kinematic equations under the assumption that acceleration is constant
perl
  • perl
might as well write them all out :)
anonymous
  • anonymous
Help me
perl
  • perl
youre doing good
perl
  • perl
there are 4 kinematic equations under constant acceleration
anonymous
  • anonymous
Gotto go i told everything would need to do this problem
anonymous
  • anonymous
i used x=xknot+vknot(t)+.5a(t)^2 where x= position, v=velocity a=acceleration and t= time
anonymous
  • anonymous
i solved for and the plugged it into v=vknot+a(t) and solved for vknot
anonymous
  • anonymous
|dw:1328860422815:dw|

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