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anonymous

  • 4 years ago

a car is traveling in a straight line and decelerating at a constant rate. after 3.2 seconds it has traveled 88m and slowed to a speed of 27 m/s what is the initial speed i got 52 m/s

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  1. anonymous
    • 4 years ago
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    \[v^2-2as=u^2\]

  2. perl
    • 4 years ago
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    what does s and u stand for?

  3. anonymous
    • 4 years ago
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    Put \[a=\frac{v-u}{t}\]

  4. anonymous
    • 4 years ago
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    s distance u initial velocity

  5. anonymous
    • 4 years ago
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    and the plug a back into the equation that is what i did but im not sure if my math is right

  6. anonymous
    • 4 years ago
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    other people had like 97m/s which didnt make sense to me

  7. perl
    • 4 years ago
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    v is final velocity, u is initial velocity

  8. anonymous
    • 4 years ago
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    Better use \[s=ut+\frac{1}{2}at^2\]

  9. perl
    • 4 years ago
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    so youre using kinematic equations under the assumption that acceleration is constant

  10. perl
    • 4 years ago
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    might as well write them all out :)

  11. anonymous
    • 4 years ago
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    Help me

  12. perl
    • 4 years ago
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    youre doing good

  13. perl
    • 4 years ago
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    there are 4 kinematic equations under constant acceleration

  14. anonymous
    • 4 years ago
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    Gotto go i told everything would need to do this problem

  15. anonymous
    • 4 years ago
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    i used x=xknot+vknot(t)+.5a(t)^2 where x= position, v=velocity a=acceleration and t= time

  16. anonymous
    • 4 years ago
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    i solved for and the plugged it into v=vknot+a(t) and solved for vknot

  17. anonymous
    • 4 years ago
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    |dw:1328860422815:dw|

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