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perl
 4 years ago
Maggie has a kite with the dimensions shown below. What is the width of the kite?
perl
 4 years ago
Maggie has a kite with the dimensions shown below. What is the width of the kite?

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perl
 4 years ago
Best ResponseYou've already chosen the best response.0im not sure what theorem is used here

Directrix
 4 years ago
Best ResponseYou've already chosen the best response.3dw:1328862799911:dwTo find x, this theorem is used. If an altitude is drawn to the hypotenuse of a right triangle, the length of the altitude is the geometric mean between the lengths of the segments of the hypotenuse.

Directrix
 4 years ago
Best ResponseYou've already chosen the best response.311 is to x as x is to 25. 11/x = x/25 x^2 = 25*11 x = 5 √ 11

Directrix
 4 years ago
Best ResponseYou've already chosen the best response.3The width of the kite is 2 times ( 5 √ 11 = 10 √ 11

perl
 4 years ago
Best ResponseYou've already chosen the best response.0woops, didnt see that right angle there, yes makes sense now

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0You don't need that theorem just use pyhtagoras theorem on the three triangles. If the remainng side lenghts are y and z. x^2+25^2=y^2 and x^2+11^2=z^2. and y^2+z^2=36^2. 2x^2+25^2+11^2=36^2.

perl
 4 years ago
Best ResponseYou've already chosen the best response.0where are you getting y^2 + z^2 = 36^2

perl
 4 years ago
Best ResponseYou've already chosen the best response.0oh i see, yes you can prove it that way

perl
 4 years ago
Best ResponseYou've already chosen the best response.0so you actually proved the general result dw:1328881279082:dw

perl
 4 years ago
Best ResponseYou've already chosen the best response.0and after doing some algebra we have h = sqrt (ab)

perl
 4 years ago
Best ResponseYou've already chosen the best response.0so this geometric mean theorem falls out from pythagorean theorem

radar
 4 years ago
Best ResponseYou've already chosen the best response.0Or properties of similar triangles (proportions) a:h :: h:b 11:h :: h:25 \[h ^{2}=11 X 25\]\[h = \sqrt{11X25}=5\sqrt{11}\]
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