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anonymous
 4 years ago
let z and w be complex numbers such that z+w=0 and z square+w square=1,then mod of zw=?.
anonymous
 4 years ago
let z and w be complex numbers such that z+w=0 and z square+w square=1,then mod of zw=?.

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perl
 4 years ago
Best ResponseYou've already chosen the best response.2so you want the modular distance of zw

perl
 4 years ago
Best ResponseYou've already chosen the best response.2 z w  = (zw) conjugat ( z w)

perl
 4 years ago
Best ResponseYou've already chosen the best response.2you need some formulas http://en.wikipedia.org/wiki/Complex_conjugation

perl
 4 years ago
Best ResponseYou've already chosen the best response.2z^2 = z* z' , where z' is the conjugate

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0thanks fr ur help but i was not getting the answer i got it now :)

perl
 4 years ago
Best ResponseYou've already chosen the best response.2can you type out the answer :)

perl
 4 years ago
Best ResponseYou've already chosen the best response.2z^2 + w^2 = 1 (z + wi) (zwi)= 1

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0do u want a solution?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0mark the two equations as (1) and (2) from (1),we get w=z, then 2z square=1 z=+_1/root2 for z=+1/root2,w=1/root2 for z=1/root2,w=+1/root2 so,mod of zw=root2

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0sorry,i forgot to write root in the previous answr hope you ll get this solution its written in a bit puzzling manner :P

perl
 4 years ago
Best ResponseYou've already chosen the best response.2makes sense, mod of zw just becomes the real number root 2
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