anonymous
  • anonymous
let z and w be complex numbers such that z+w=0 and z square+w square=1,then mod of z-w=?.
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
perl
  • perl
so you want the modular distance of z-w
perl
  • perl
| z-w| = sqrt ( z-w)^2 =
perl
  • perl
, sorry messed up

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More answers

perl
  • perl
| z- w | = (z-w) conjugat ( z- w)
perl
  • perl
you need some formulas http://en.wikipedia.org/wiki/Complex_conjugation
perl
  • perl
|z|^2 = z* z' , where z' is the conjugate
perl
  • perl
and |z| is mod z
anonymous
  • anonymous
thanks fr ur help but i was not getting the answer i got it now :)
perl
  • perl
can you type out the answer :)
perl
  • perl
z^2 + w^2 = 1 (z + wi) (z-wi)= 1
anonymous
  • anonymous
2
anonymous
  • anonymous
do u want a solution?
perl
  • perl
yes
anonymous
  • anonymous
mark the two equations as (1) and (2) from (1),we get w=-z, then 2z square=1 z=+_1/root2 for z=+1/root2,w=-1/root2 for z=-1/root2,w=+1/root2 so,mod of z-w=root2
anonymous
  • anonymous
sorry,i forgot to write root in the previous answr hope you ll get this solution its written in a bit puzzling manner :P
perl
  • perl
makes sense, mod of z-w just becomes the real number root 2
anonymous
  • anonymous
hmmm..right !

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