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anonymous

  • 4 years ago

let z and w be complex numbers such that z+w=0 and z square+w square=1,then mod of z-w=?.

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  1. perl
    • 4 years ago
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    so you want the modular distance of z-w

  2. perl
    • 4 years ago
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    | z-w| = sqrt ( z-w)^2 =

  3. perl
    • 4 years ago
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    , sorry messed up

  4. perl
    • 4 years ago
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    | z- w | = (z-w) conjugat ( z- w)

  5. perl
    • 4 years ago
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    you need some formulas http://en.wikipedia.org/wiki/Complex_conjugation

  6. perl
    • 4 years ago
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    |z|^2 = z* z' , where z' is the conjugate

  7. perl
    • 4 years ago
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    and |z| is mod z

  8. anonymous
    • 4 years ago
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    thanks fr ur help but i was not getting the answer i got it now :)

  9. perl
    • 4 years ago
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    can you type out the answer :)

  10. perl
    • 4 years ago
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    z^2 + w^2 = 1 (z + wi) (z-wi)= 1

  11. anonymous
    • 4 years ago
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    2

  12. anonymous
    • 4 years ago
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    do u want a solution?

  13. perl
    • 4 years ago
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    yes

  14. anonymous
    • 4 years ago
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    mark the two equations as (1) and (2) from (1),we get w=-z, then 2z square=1 z=+_1/root2 for z=+1/root2,w=-1/root2 for z=-1/root2,w=+1/root2 so,mod of z-w=root2

  15. anonymous
    • 4 years ago
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    sorry,i forgot to write root in the previous answr hope you ll get this solution its written in a bit puzzling manner :P

  16. perl
    • 4 years ago
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    makes sense, mod of z-w just becomes the real number root 2

  17. anonymous
    • 4 years ago
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    hmmm..right !

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