Show that every point on the curve y=b sin (x/a), where the curve meets the axes of x, is a point of inflextion.
Do i have to plainly show that x=0 is a POI or its asking for something else?
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inflection tends to be a found by a second derivative; and tested for cavage
yeah i know that, but the language isnt very clear up there.
looks like: -b sin(x/a)/a^2 is the second derivative to me
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since b=0 is trivial; it looks to be what x/a = any mutiple of pi
sorry didnt get that.
how to "show" it? i aint got a clue
sin(n*pi) = 0
so when x/a = n*pi we are at zero
yeah thats where i came, so is that the answer fianlly, x=0
x = a n*pi would seem to be the answer to me; but since n is an arbitrary integer then a*n would have to be an interger as well.
other than that; I got no idea what the "answer" might entail ....
umm, it says, where the curve meets the axes of x, so y=0 at that point, this only gives x=0.
inflection point is where the second derivative changes sign.
we know that
y=b sin (x/a)
crosses the x-axis when x/a is some multiple of 2pi
the 2nd derivative at these same points is -b sin(x/a)/a^2 = 0
also, if we go a dx distance below x/a and a little distance dx above x/a, the 2nd derivative changes sign. So we are at an inflection point.
That seems clear, understood, thank you phi and amistre for your time :)
*crosses the x-axis when x/a is some multiple of pi