Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing


  • 4 years ago

A rifle is aimed horizontally at a target 55.0 m away. The bullet hits the target 3.00 cm below the aim point What was the bullet's flight time? What was the bullet's speed as it left the barrel?

  • This Question is Closed
  1. shubham
    • 4 years ago
    Best Response
    You've already chosen the best response.
    Medals 3

    Initial vertical velocity, Vy = 0. So, time of flight = time taken by bullet to fall 3 cm vertically. Use S = 1/2*a*t^2 t = sqrt.( 2s/a) t= sqrt.(2*0.03/9.8) sec.

  2. Not the answer you are looking for?
    Search for more explanations.

    • Attachments:

Ask your own question

Sign Up
Find more explanations on OpenStudy
Privacy Policy