anonymous
  • anonymous
At what POINTS is this function continuous..y=cosx/x...someone please explain to me how to solve these types of problems? is it whatever numbers make this an undefined problem?
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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anonymous
  • anonymous
well x=/=0
anonymous
  • anonymous
i would say limit x>0 \[(-\infty,0)\]\[(0,\infty)\]
anonymous
  • anonymous
but im a nub so dont trust me much

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anonymous
  • anonymous
the book says all x except x=0 so yes ur on it, but like, do u just see this problem n knw, or do u go thru a guess n check process, what process do u go thru to get an answer for these types of problems?
anonymous
  • anonymous
well the denominator can never be 0
anonymous
  • anonymous
so x cannot be 0
anonymous
  • anonymous
not much to guess at really
anonymous
  • anonymous
just means if x were zero
anonymous
  • anonymous
the value would be undefined
anonymous
  • anonymous
hence a hole in your graph
anonymous
  • anonymous
got it! ok i got one more...
anonymous
  • anonymous
y=sqrt(2x+3)
anonymous
  • anonymous
well since it is a square root is can never be negative
anonymous
  • anonymous
so it would be \[(0,\infty)\]
anonymous
  • anonymous
the graph of a square root function looks like
anonymous
  • anonymous
|dw:1328895361125:dw|
anonymous
  • anonymous
the books answer is, all X greater than or equal to -3/2
anonymous
  • anonymous
yea thats right
anonymous
  • anonymous
because
anonymous
  • anonymous
y=sqrt(2x+3)
anonymous
  • anonymous
to make the square root 0 x would have to be -3/2
anonymous
  • anonymous
hence its still not a negative
anonymous
  • anonymous
been up all night sorry
anonymous
  • anonymous
getting tired
anonymous
  • anonymous
but since -3/2 make it the sqrt of 0 thats the limit
anonymous
  • anonymous
all other numbers have toi be greater then -3/2
anonymous
  • anonymous
so if u plug in -3/2 "sqrt(2(-3/2)+3" this will equal 0?
anonymous
  • anonymous
yes because the 2's cancel
anonymous
  • anonymous
2x-3/2 = -3
anonymous
  • anonymous
-3+3 = 0
anonymous
  • anonymous
got it! so on these types of problems are u really just looking for w/e numbers will make it undefined?
anonymous
  • anonymous
basically
anonymous
  • anonymous
and if you cannot make it undefined
anonymous
  • anonymous
its continuous from -inf to +inf
anonymous
  • anonymous
ok well you have a good one, gotta get some rest now
anonymous
  • anonymous
thanks!

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