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chemmaj88
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At what POINTS is this function continuous..y=cosx/x...someone please explain to me how to solve these types of problems? is it whatever numbers make this an undefined problem?
 2 years ago
 2 years ago
chemmaj88 Group Title
At what POINTS is this function continuous..y=cosx/x...someone please explain to me how to solve these types of problems? is it whatever numbers make this an undefined problem?
 2 years ago
 2 years ago

This Question is Closed

ChrisV Group TitleBest ResponseYou've already chosen the best response.1
i would say limit x>0 \[(\infty,0)\]\[(0,\infty)\]
 2 years ago

ChrisV Group TitleBest ResponseYou've already chosen the best response.1
but im a nub so dont trust me much
 2 years ago

chemmaj88 Group TitleBest ResponseYou've already chosen the best response.0
the book says all x except x=0 so yes ur on it, but like, do u just see this problem n knw, or do u go thru a guess n check process, what process do u go thru to get an answer for these types of problems?
 2 years ago

ChrisV Group TitleBest ResponseYou've already chosen the best response.1
well the denominator can never be 0
 2 years ago

ChrisV Group TitleBest ResponseYou've already chosen the best response.1
so x cannot be 0
 2 years ago

ChrisV Group TitleBest ResponseYou've already chosen the best response.1
not much to guess at really
 2 years ago

ChrisV Group TitleBest ResponseYou've already chosen the best response.1
just means if x were zero
 2 years ago

ChrisV Group TitleBest ResponseYou've already chosen the best response.1
the value would be undefined
 2 years ago

ChrisV Group TitleBest ResponseYou've already chosen the best response.1
hence a hole in your graph
 2 years ago

chemmaj88 Group TitleBest ResponseYou've already chosen the best response.0
got it! ok i got one more...
 2 years ago

chemmaj88 Group TitleBest ResponseYou've already chosen the best response.0
y=sqrt(2x+3)
 2 years ago

ChrisV Group TitleBest ResponseYou've already chosen the best response.1
well since it is a square root is can never be negative
 2 years ago

ChrisV Group TitleBest ResponseYou've already chosen the best response.1
so it would be \[(0,\infty)\]
 2 years ago

ChrisV Group TitleBest ResponseYou've already chosen the best response.1
the graph of a square root function looks like
 2 years ago

ChrisV Group TitleBest ResponseYou've already chosen the best response.1
dw:1328895361125:dw
 2 years ago

chemmaj88 Group TitleBest ResponseYou've already chosen the best response.0
the books answer is, all X greater than or equal to 3/2
 2 years ago

ChrisV Group TitleBest ResponseYou've already chosen the best response.1
yea thats right
 2 years ago

ChrisV Group TitleBest ResponseYou've already chosen the best response.1
y=sqrt(2x+3)
 2 years ago

ChrisV Group TitleBest ResponseYou've already chosen the best response.1
to make the square root 0 x would have to be 3/2
 2 years ago

ChrisV Group TitleBest ResponseYou've already chosen the best response.1
hence its still not a negative
 2 years ago

ChrisV Group TitleBest ResponseYou've already chosen the best response.1
been up all night sorry
 2 years ago

ChrisV Group TitleBest ResponseYou've already chosen the best response.1
getting tired
 2 years ago

ChrisV Group TitleBest ResponseYou've already chosen the best response.1
but since 3/2 make it the sqrt of 0 thats the limit
 2 years ago

ChrisV Group TitleBest ResponseYou've already chosen the best response.1
all other numbers have toi be greater then 3/2
 2 years ago

chemmaj88 Group TitleBest ResponseYou've already chosen the best response.0
so if u plug in 3/2 "sqrt(2(3/2)+3" this will equal 0?
 2 years ago

ChrisV Group TitleBest ResponseYou've already chosen the best response.1
yes because the 2's cancel
 2 years ago

chemmaj88 Group TitleBest ResponseYou've already chosen the best response.0
got it! so on these types of problems are u really just looking for w/e numbers will make it undefined?
 2 years ago

ChrisV Group TitleBest ResponseYou've already chosen the best response.1
and if you cannot make it undefined
 2 years ago

ChrisV Group TitleBest ResponseYou've already chosen the best response.1
its continuous from inf to +inf
 2 years ago

ChrisV Group TitleBest ResponseYou've already chosen the best response.1
ok well you have a good one, gotta get some rest now
 2 years ago
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