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chemmaj88

  • 2 years ago

At what POINTS is this function continuous..y=cosx/x...someone please explain to me how to solve these types of problems? is it whatever numbers make this an undefined problem?

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  1. ChrisV
    • 2 years ago
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    well x=/=0

  2. ChrisV
    • 2 years ago
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    i would say limit x>0 \[(-\infty,0)\]\[(0,\infty)\]

  3. ChrisV
    • 2 years ago
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    but im a nub so dont trust me much

  4. chemmaj88
    • 2 years ago
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    the book says all x except x=0 so yes ur on it, but like, do u just see this problem n knw, or do u go thru a guess n check process, what process do u go thru to get an answer for these types of problems?

  5. ChrisV
    • 2 years ago
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    well the denominator can never be 0

  6. ChrisV
    • 2 years ago
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    so x cannot be 0

  7. ChrisV
    • 2 years ago
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    not much to guess at really

  8. ChrisV
    • 2 years ago
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    just means if x were zero

  9. ChrisV
    • 2 years ago
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    the value would be undefined

  10. ChrisV
    • 2 years ago
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    hence a hole in your graph

  11. chemmaj88
    • 2 years ago
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    got it! ok i got one more...

  12. chemmaj88
    • 2 years ago
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    y=sqrt(2x+3)

  13. ChrisV
    • 2 years ago
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    well since it is a square root is can never be negative

  14. ChrisV
    • 2 years ago
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    so it would be \[(0,\infty)\]

  15. ChrisV
    • 2 years ago
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    the graph of a square root function looks like

  16. ChrisV
    • 2 years ago
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    |dw:1328895361125:dw|

  17. chemmaj88
    • 2 years ago
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    the books answer is, all X greater than or equal to -3/2

  18. ChrisV
    • 2 years ago
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    yea thats right

  19. ChrisV
    • 2 years ago
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    because

  20. ChrisV
    • 2 years ago
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    y=sqrt(2x+3)

  21. ChrisV
    • 2 years ago
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    to make the square root 0 x would have to be -3/2

  22. ChrisV
    • 2 years ago
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    hence its still not a negative

  23. ChrisV
    • 2 years ago
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    been up all night sorry

  24. ChrisV
    • 2 years ago
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    getting tired

  25. ChrisV
    • 2 years ago
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    but since -3/2 make it the sqrt of 0 thats the limit

  26. ChrisV
    • 2 years ago
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    all other numbers have toi be greater then -3/2

  27. chemmaj88
    • 2 years ago
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    so if u plug in -3/2 "sqrt(2(-3/2)+3" this will equal 0?

  28. ChrisV
    • 2 years ago
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    yes because the 2's cancel

  29. ChrisV
    • 2 years ago
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    2x-3/2 = -3

  30. ChrisV
    • 2 years ago
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    -3+3 = 0

  31. chemmaj88
    • 2 years ago
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    got it! so on these types of problems are u really just looking for w/e numbers will make it undefined?

  32. ChrisV
    • 2 years ago
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    basically

  33. ChrisV
    • 2 years ago
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    and if you cannot make it undefined

  34. ChrisV
    • 2 years ago
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    its continuous from -inf to +inf

  35. ChrisV
    • 2 years ago
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    ok well you have a good one, gotta get some rest now

  36. chemmaj88
    • 2 years ago
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    thanks!

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