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KingJ

  • 2 years ago

What is the sum of the arithmetic sequence 8, 14, 20 …, if there are 24 terms?

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  1. adnanchowdhury
    • 2 years ago
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    S = 2a + (n-1)d Where a = first number in sequence, n is nth term you are looking for and d is the common difference.

  2. adnanchowdhury
    • 2 years ago
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    sorry, it should be: S = n/2( 2a + (n-1)d)

  3. Mertsj
    • 2 years ago
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    \[s _{n}=\frac{n}{2}(a _{1}+a _{n})\] To find the 24th term use: \[a _{n}=a _{1}+(n-1)d=8+(24-1)6=146\] \[s _{n}=\frac{24}{2}(6+146)\] \[s _{n}=1824\]

  4. Mertsj
    • 2 years ago
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    There. I think I finally got it right.

  5. KingJ
    • 2 years ago
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    THANK YOU

  6. Mertsj
    • 2 years ago
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    yw

  7. cinar
    • 2 years ago
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    |dw:1328989953105:dw|

  8. cinar
    • 2 years ago
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    1848

  9. cinar
    • 2 years ago
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    you put a1=6 but it is 8

  10. cinar
    • 2 years ago
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    |dw:1328990276982:dw|

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