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What is the sum of the arithmetic sequence 8, 14, 20 …, if there are 24 terms?
 2 years ago
 2 years ago
What is the sum of the arithmetic sequence 8, 14, 20 …, if there are 24 terms?
 2 years ago
 2 years ago

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adnanchowdhuryBest ResponseYou've already chosen the best response.0
S = 2a + (n1)d Where a = first number in sequence, n is nth term you are looking for and d is the common difference.
 2 years ago

adnanchowdhuryBest ResponseYou've already chosen the best response.0
sorry, it should be: S = n/2( 2a + (n1)d)
 2 years ago

MertsjBest ResponseYou've already chosen the best response.1
\[s _{n}=\frac{n}{2}(a _{1}+a _{n})\] To find the 24th term use: \[a _{n}=a _{1}+(n1)d=8+(241)6=146\] \[s _{n}=\frac{24}{2}(6+146)\] \[s _{n}=1824\]
 2 years ago

MertsjBest ResponseYou've already chosen the best response.1
There. I think I finally got it right.
 2 years ago
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