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The sum of two numbers is 3. The difference of the squares of the numbers is 33. What is the absolute value of the difference of the two numbers?
 2 years ago
 2 years ago
The sum of two numbers is 3. The difference of the squares of the numbers is 33. What is the absolute value of the difference of the two numbers?
 2 years ago
 2 years ago

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MissPacGirlBest ResponseYou've already chosen the best response.0
x+y=3 (x+y)(x=y)=33 xy=a
 2 years ago

MissPacGirlBest ResponseYou've already chosen the best response.0
oops, I meant (xy) not (x=y)
 2 years ago

adnanchowdhuryBest ResponseYou've already chosen the best response.0
\[a  b = 3\] \[a ^{2}  b ^{2} = 33\] Rearrange eqaution 1: b = 3a Substitute into equation 2: \[a ^{2}  (3a) ^{2} = 33\] Solve for a...
 2 years ago

MissPacGirlBest ResponseYou've already chosen the best response.0
I substituted so ir is 3(xy)=33 divided 3 from both sides. xy=33/3 xy=11 absolute value of 11 is 11.
 2 years ago

satellite73Best ResponseYou've already chosen the best response.2
\[x+y=3\] \[x^2y^2=33\] \[(x+y)(xy)=33\] \[xy=\frac{33}{x+y}\] \[xy=\frac{33}{3}=11\]
 2 years ago

MissPacGirlBest ResponseYou've already chosen the best response.0
I did it a bit different, but that's okay! :D
 2 years ago

adnanchowdhuryBest ResponseYou've already chosen the best response.0
Yes, you way is better.
 2 years ago

nenadmatematikaBest ResponseYou've already chosen the best response.0
just a second 7+(4)=3 and 7^24^2=33 so the numbers are 7 and 4...oh no I'm sorry it's the absolute value of the DIFFERENCE...:D sorry :D you're right :D
 2 years ago
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