## A community for students. Sign up today

Here's the question you clicked on:

## MissPacGirl 3 years ago The sum of two numbers is 3. The difference of the squares of the numbers is 33. What is the absolute value of the difference of the two numbers?

• This Question is Closed
1. MissPacGirl

x+y=3 (x+y)(x=y)=33 x-y=|a|

2. nenadmatematika

3

3. MissPacGirl

oops, I meant (x-y) not (x=y)

4. MissPacGirl

it is actually 11.

5. adnanchowdhury

$a - b = 3$ $a ^{2} - b ^{2} = 33$ Rearrange eqaution 1: b = 3-a Substitute into equation 2: $a ^{2} - (3-a) ^{2} = 33$ Solve for a...

6. MissPacGirl

I substituted so ir is 3(x-y)=33 divided 3 from both sides. x-y=33/3 x-y=11 absolute value of 11 is 11.

7. satellite73

$x+y=3$ $x^2-y^2=33$ $(x+y)(x-y)=33$ $x-y=\frac{33}{x+y}$ $x-y=\frac{33}{3}=11$

8. MissPacGirl

I did it a bit different, but that's okay! :D

9. adnanchowdhury

Yes, you way is better.

10. nenadmatematika

just a second 7+(-4)=3 and 7^2-4^2=33 so the numbers are 7 and -4...oh no I'm sorry it's the absolute value of the DIFFERENCE...:D sorry :D you're right :D

#### Ask your own question

Sign Up
Find more explanations on OpenStudy
Privacy Policy