Got Homework?
Connect with other students for help. It's a free community.
Here's the question you clicked on:
 0 viewing
c0c0pIe
Group Title
A 200 g particle gains a momentum of 25 Ns in 12 s starting from rest. Find the
kinetic energy of the particle and the applied force.
 2 years ago
 2 years ago
c0c0pIe Group Title
A 200 g particle gains a momentum of 25 Ns in 12 s starting from rest. Find the kinetic energy of the particle and the applied force.
 2 years ago
 2 years ago

This Question is Closed

dave444 Group TitleBest ResponseYou've already chosen the best response.2
We are given the mass of the particle m=200 g = 0.2 kg. And the momentum p = 25 Ns = 25 kg m/s. We know \(p=mv\) and kinetic energy \(E_k = \frac{1}{2}mv^2\). Multiplying numerator and denominator of the expression for \(E_k\) by m, we get: \[E_k = \frac{p^2}{2m} \] Plugging in our given quantities, yields: \[E_k = 1562.5\ \mathrm{J}\] Assuming a constant force, we can use the impulse/momentum equation: \[F\Delta t = \Delta p\] Since we are starting from rest \(\Delta p = p\), and we are given \(\Delta t = 12\mathrm{s}\). So that: \[F = \frac{p}{\Delta t} = \frac{25\ \mathrm{Ns}}{12s} = 2.08\ \mathrm{N}\]
 2 years ago
See more questions >>>
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.