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allyfranken
find the first partial derivative: f(x, y) = y^5 -3xy could you please explain how to do these as well?
with respect to x or y ?
partials are just like usual except the none interested in variable is considered a constant
Well, there's two partial derivatives, one with respect to x and one with respect to y. To find the partial derivative with respect to x you differentiate with respect to x while holding y constant, giving: \[\frac{\partial f}{\partial x} = -3y\] Similarly, \[\frac{\partial f}{\partial y} = 5y^4-3x\]
x y^2 with respect to x is: y^2 x y^2 with respect to y is: 2x y