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anonymous
 4 years ago
a gardener has 46ft of fencing to be used to enclose a rectangular garden that has a border 2 feet wide surrounding it. if the length of the garden is to be twice its width, what will be the dimensions of the garden?
anonymous
 4 years ago
a gardener has 46ft of fencing to be used to enclose a rectangular garden that has a border 2 feet wide surrounding it. if the length of the garden is to be twice its width, what will be the dimensions of the garden?

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Hero
 4 years ago
Best ResponseYou've already chosen the best response.1dw:1328999809861:dw Can you figure it out from here?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0so it would be 2(2x+4)+2(x+4)=P ?

Hero
 4 years ago
Best ResponseYou've already chosen the best response.1You can always count on mertsj to crash the party

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0p=perimeter....so that equation would be correct tho?

Hero
 4 years ago
Best ResponseYou've already chosen the best response.1What do you think the 46 is for?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0ahhh i wasn't sure...

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0There are 46 feet of fence, so P=46.

Hero
 4 years ago
Best ResponseYou've already chosen the best response.1Mertsj, when you see me helping a student, I don't think you should interfere like that. You're the only person here that does that and I don't appreciate it. I will be discussing this with the mods. I've asked you countless times to respect my wishes, but you continue to ignore me.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0you are my hero, hero! i appreciate that you didnt give me the final answer so that i could try and figure it out myself

Hero
 4 years ago
Best ResponseYou've already chosen the best response.1Okay, not to worry. I will discuss this issue with the mods and hopefully get a resolution we can all agree with. The only problem is, mertsj seems to not want to communicate with me, which makes the matter much more difficult. I will be directing the mods and administrators to this chat. Thanks for providing your feedback regarding this. That helps a lot.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0ok, so part b of this problem is finding the area of the garden. if the area is the length times the width would the equation be a=(x+4)(2x +4) and would a=46 squared?

Hero
 4 years ago
Best ResponseYou've already chosen the best response.1Yes, however, it will be much more easier to solve if you use the first equation you created to solve for x.

Hero
 4 years ago
Best ResponseYou've already chosen the best response.1The one you created where you included the P variable.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0oh so just plug in 5 for x?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0i got a=126 but the book says the answer is 50 sq ft...

Hero
 4 years ago
Best ResponseYou've already chosen the best response.1So me the work you did to find the area

Hero
 4 years ago
Best ResponseYou've already chosen the best response.1Show all of your work actually...For both perimeter and area

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0a= (x+4)(2x+4) a= (5+4)(2(5)+4) a=(9)(14) a=126

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0p=2(x+4)+2(2x+4)=46 2x+8+4x+8=46 6x+16=46\ 6x=30 x=5; 2x=10 5 by 10

Hero
 4 years ago
Best ResponseYou've already chosen the best response.1Yes, that is correct. Is that your corrected solution?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0the book says the area is 50 sq ft, not 126

Hero
 4 years ago
Best ResponseYou've already chosen the best response.1The solution is indeed 50. For next time, you have to read the question more carefully so that you can avoid making such mistakes.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0ohhhhh so the inside then not the fencing....

Hero
 4 years ago
Best ResponseYou've already chosen the best response.1Read the original question again

Hero
 4 years ago
Best ResponseYou've already chosen the best response.1It asked for the dimensions of the garden, not the fencing

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0haha ok so a gardener has 46 ft of fencing to be used to enclose a rectangular garden that has a border of 2 ft wide surrounding it. so the area of that would be a=2x?

Hero
 4 years ago
Best ResponseYou've already chosen the best response.1But you already calculated the correct area. I don't understand how you're still confused about this.
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