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a gardener has 46ft of fencing to be used to enclose a rectangular garden that has a border 2 feet wide surrounding it. if the length of the garden is to be twice its width, what will be the dimensions of the garden?
 2 years ago
 2 years ago
a gardener has 46ft of fencing to be used to enclose a rectangular garden that has a border 2 feet wide surrounding it. if the length of the garden is to be twice its width, what will be the dimensions of the garden?
 2 years ago
 2 years ago

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HeroBest ResponseYou've already chosen the best response.0
dw:1328999809861:dw Can you figure it out from here?
 2 years ago

gwynne8188Best ResponseYou've already chosen the best response.1
so it would be 2(2x+4)+2(x+4)=P ?
 2 years ago

HeroBest ResponseYou've already chosen the best response.0
You can always count on mertsj to crash the party
 2 years ago

gwynne8188Best ResponseYou've already chosen the best response.1
p=perimeter....so that equation would be correct tho?
 2 years ago

HeroBest ResponseYou've already chosen the best response.0
What do you think the 46 is for?
 2 years ago

gwynne8188Best ResponseYou've already chosen the best response.1
ahhh i wasn't sure...
 2 years ago

dave444Best ResponseYou've already chosen the best response.0
There are 46 feet of fence, so P=46.
 2 years ago

HeroBest ResponseYou've already chosen the best response.0
Mertsj, when you see me helping a student, I don't think you should interfere like that. You're the only person here that does that and I don't appreciate it. I will be discussing this with the mods. I've asked you countless times to respect my wishes, but you continue to ignore me.
 2 years ago

gwynne8188Best ResponseYou've already chosen the best response.1
you are my hero, hero! i appreciate that you didnt give me the final answer so that i could try and figure it out myself
 2 years ago

HeroBest ResponseYou've already chosen the best response.0
Okay, not to worry. I will discuss this issue with the mods and hopefully get a resolution we can all agree with. The only problem is, mertsj seems to not want to communicate with me, which makes the matter much more difficult. I will be directing the mods and administrators to this chat. Thanks for providing your feedback regarding this. That helps a lot.
 2 years ago

gwynne8188Best ResponseYou've already chosen the best response.1
ok, so part b of this problem is finding the area of the garden. if the area is the length times the width would the equation be a=(x+4)(2x +4) and would a=46 squared?
 2 years ago

HeroBest ResponseYou've already chosen the best response.0
Yes, however, it will be much more easier to solve if you use the first equation you created to solve for x.
 2 years ago

HeroBest ResponseYou've already chosen the best response.0
The one you created where you included the P variable.
 2 years ago

gwynne8188Best ResponseYou've already chosen the best response.1
oh so just plug in 5 for x?
 2 years ago

gwynne8188Best ResponseYou've already chosen the best response.1
i got a=126 but the book says the answer is 50 sq ft...
 2 years ago

HeroBest ResponseYou've already chosen the best response.0
So me the work you did to find the area
 2 years ago

HeroBest ResponseYou've already chosen the best response.0
Show all of your work actually...For both perimeter and area
 2 years ago

gwynne8188Best ResponseYou've already chosen the best response.1
a= (x+4)(2x+4) a= (5+4)(2(5)+4) a=(9)(14) a=126
 2 years ago

gwynne8188Best ResponseYou've already chosen the best response.1
p=2(x+4)+2(2x+4)=46 2x+8+4x+8=46 6x+16=46\ 6x=30 x=5; 2x=10 5 by 10
 2 years ago

HeroBest ResponseYou've already chosen the best response.0
Yes, that is correct. Is that your corrected solution?
 2 years ago

gwynne8188Best ResponseYou've already chosen the best response.1
the book says the area is 50 sq ft, not 126
 2 years ago

HeroBest ResponseYou've already chosen the best response.0
The solution is indeed 50. For next time, you have to read the question more carefully so that you can avoid making such mistakes.
 2 years ago

gwynne8188Best ResponseYou've already chosen the best response.1
ohhhhh so the inside then not the fencing....
 2 years ago

HeroBest ResponseYou've already chosen the best response.0
Read the original question again
 2 years ago

HeroBest ResponseYou've already chosen the best response.0
It asked for the dimensions of the garden, not the fencing
 2 years ago

gwynne8188Best ResponseYou've already chosen the best response.1
haha ok so a gardener has 46 ft of fencing to be used to enclose a rectangular garden that has a border of 2 ft wide surrounding it. so the area of that would be a=2x?
 2 years ago

HeroBest ResponseYou've already chosen the best response.0
But you already calculated the correct area. I don't understand how you're still confused about this.
 2 years ago
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