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rachna

  • 2 years ago

Determine if (y=tan x + sec x) has any maximums or minimums for -pi/2 < x < pi/2 and justify your answer.

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  1. amitlpu91
    • 2 years ago
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    jst take dy/dx

  2. badreferences
    • 2 years ago
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    y'=sec(x)^2+sin(x), y'=0 when sec(x)^2=-sin(x), solve, profit!

  3. rachna
    • 2 years ago
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    thanks!!

  4. rachna
    • 2 years ago
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    wait how dou get sin(x)??

  5. badreferences
    • 2 years ago
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    Oh, sin(x) was my mistake.

  6. badreferences
    • 2 years ago
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    Apparently, I'm still bad at calculus. XP It should be (sin(x))(cos(x)^-2).

  7. rachna
    • 2 years ago
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    i thought derivative of sec x is sec x tan x

  8. amitlpu91
    • 2 years ago
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    yea........

  9. badreferences
    • 2 years ago
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    sin(x)/cos(x)^2=tan(x)/cos(x)=tan(x)sec(x)

  10. badreferences
    • 2 years ago
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    Same thing. I just didn't remember it, I had to prove it out.

  11. rachna
    • 2 years ago
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    ok so what i do now after i got the derivative ??

  12. badreferences
    • 2 years ago
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    sec(x)^2+tan(x)sec(x)=y'=0, tan(x)+1=0, tan(x)=-1, x=arctan(-1)

  13. badreferences
    • 2 years ago
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    Woops, my bad. Wait a sec.

  14. badreferences
    • 2 years ago
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    (sec(x)+tan(x))=0, tan(x)=-sec(x)

  15. badreferences
    • 2 years ago
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    there we go. when do tan(x) and -sec(x) intersect?

  16. rachna
    • 2 years ago
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    wait a minute i need to look at unit circle, i dont have those memorized

  17. badreferences
    • 2 years ago
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    sin(x)/cos(x)=-1/cos(x), sin(x)=-1 when is this true?

  18. rachna
    • 2 years ago
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    i think 3pi/4, 7pi/4

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