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TomLikesPhysics
 3 years ago
If I want to integrate (sinx)^2 using the method of substitution than what are my function g and g`? x would be pointless because than I would just replace the x with a t but sinx also does not seem to work because there is no cosx.
TomLikesPhysics
 3 years ago
If I want to integrate (sinx)^2 using the method of substitution than what are my function g and g`? x would be pointless because than I would just replace the x with a t but sinx also does not seem to work because there is no cosx.

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NotSObright
 3 years ago
Best ResponseYou've already chosen the best response.1Replace cos x by sqrt(1t^2)

NotSObright
 3 years ago
Best ResponseYou've already chosen the best response.1But going by this method is possible and feasible but not smart

NotSObright
 3 years ago
Best ResponseYou've already chosen the best response.1\[\int\limits_{}^{}\frac{t^2}{\sqrt{1t^2}}dt\]

NotSObright
 3 years ago
Best ResponseYou've already chosen the best response.1\[\int\limits_{}^{}\sqrt{1t^2}\frac{1}{\sqrt{1t^2}}\]

TomLikesPhysics
 3 years ago
Best ResponseYou've already chosen the best response.1How do you get from one term (the t^2 over sth.) to the two separate terms? At first I followed my instincts and got to the t^2 over such and such term but I thought this is a deadend.

Mani_Jha
 3 years ago
Best ResponseYou've already chosen the best response.0\[\int\limits_{}^{}t ^{2}/\sqrt{1t ^{2}}=\int\limits_{}^{}(1t ^{2}1)/\sqrt{1t ^{2}}\] =\[\int\limits_{}^{}(1t ^{2})/\sqrt{1t ^{2}}1/\sqrt{1t ^{2}}\]. That's how he got there

TomLikesPhysics
 3 years ago
Best ResponseYou've already chosen the best response.1Ok, that would have never come to my mind. Thank you for your explanation. I just figured out that it is quite easy to do this integral if I write instead of (sinx)^2 just 0.50.5*cos2x.
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