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tfguss

I'm not sure where to start. The drawing shows two crates that are connected by a steel wire that passes over a pulley. The unstretched length of the wire is 2.0 m, and its cross-sectional area is 1.6 *10^-5 [m^2]. The pulley is frictionless and massless. When the crates are accelerating, determine the change in length of the wire. Ignore the mass of the wire.

  • 2 years ago
  • 2 years ago

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  1. tfguss
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    Attached is the image. Please help!

    • 2 years ago
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  2. hosein
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    your goal is tension ?

    • 2 years ago
  3. tfguss
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    Yes

    • 2 years ago
  4. tfguss
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    Young's modulus of steel is 200gPa I think- how do I factor in the weight? I tried the usual deformation formula using 9.81*(m1+m2) as the force in newtons, but this does not yield the answer. I'm confused.

    • 2 years ago
  5. banditelol
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    what is the cross sectional area means?

    • 2 years ago
  6. tfguss
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    That is the area across the end of the wire, aka you cut the wire in half and its the area of the circle at the end of the wire.

    • 2 years ago
  7. banditelol
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    oooo.. I think you should just search the tension by using the (sigma)F=ma for both crates, and just use the modulus young equation to search for the change of length

    • 2 years ago
  8. banditelol
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    |dw:1329064147162:dw| in which, Y=modulus young F= the tension(in this case I think 2 times the rope's tension) A = cross sectional area l = the original length (delta) l = the change of length

    • 2 years ago
  9. hosein
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    do you know relation of atwood acceleration & tesion ? use from that

    • 2 years ago
  10. hosein
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    \[T=2m _{1}m _{2}g/m _{1}+m _{2}\] for more see this: http://en.wikipedia.org/wiki/Atwood_machine

    • 2 years ago
  11. hosein
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    did you get it?

    • 2 years ago
  12. tfguss
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    Yes! Thank you!

    • 2 years ago
  13. hosein
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    your wellcome

    • 2 years ago
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