anonymous
  • anonymous
I'm not sure where to start. The drawing shows two crates that are connected by a steel wire that passes over a pulley. The unstretched length of the wire is 2.0 m, and its cross-sectional area is 1.6 *10^-5 [m^2]. The pulley is frictionless and massless. When the crates are accelerating, determine the change in length of the wire. Ignore the mass of the wire.
Physics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
Attached is the image. Please help!
1 Attachment
anonymous
  • anonymous
your goal is tension ?
anonymous
  • anonymous
Yes

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anonymous
  • anonymous
Young's modulus of steel is 200gPa I think- how do I factor in the weight? I tried the usual deformation formula using 9.81*(m1+m2) as the force in newtons, but this does not yield the answer. I'm confused.
anonymous
  • anonymous
what is the cross sectional area means?
anonymous
  • anonymous
That is the area across the end of the wire, aka you cut the wire in half and its the area of the circle at the end of the wire.
anonymous
  • anonymous
oooo.. I think you should just search the tension by using the (sigma)F=ma for both crates, and just use the modulus young equation to search for the change of length
anonymous
  • anonymous
|dw:1329064147162:dw| in which, Y=modulus young F= the tension(in this case I think 2 times the rope's tension) A = cross sectional area l = the original length (delta) l = the change of length
anonymous
  • anonymous
do you know relation of atwood acceleration & tesion ? use from that
anonymous
  • anonymous
\[T=2m _{1}m _{2}g/m _{1}+m _{2}\] for more see this: http://en.wikipedia.org/wiki/Atwood_machine
anonymous
  • anonymous
did you get it?
anonymous
  • anonymous
Yes! Thank you!
anonymous
  • anonymous
your wellcome

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