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hosein
 3 years ago
Best ResponseYou've already chosen the best response.1i think these formulas for that : F=qe &F=ma & this equation :\[y=(1/2)at ^{2}\] if simplify these we have: \[y=(1/2)(qE/m)t ^{2}\] solve this with t=1 E is electric field act on drop

hosein
 3 years ago
Best ResponseYou've already chosen the best response.1sorry in first formula F=qE not f=qe

hosein
 3 years ago
Best ResponseYou've already chosen the best response.1first say me by the times means any 1 second?

hosein
 3 years ago
Best ResponseYou've already chosen the best response.1if no put t=L/V in the y=(1/2)at^2

hosein
 3 years ago
Best ResponseYou've already chosen the best response.1for m use this\[\rho=m/(4/3\Pi r ^{3})\]

95123
 3 years ago
Best ResponseYou've already chosen the best response.0i used mastering physics and it tell me its wrong

95123
 3 years ago
Best ResponseYou've already chosen the best response.0i have another Q can u help me

hosein
 3 years ago
Best ResponseYou've already chosen the best response.1i don't solve please wait what's your Q?

hosein
 3 years ago
Best ResponseYou've already chosen the best response.1ohh this is a another ask am iright?

hosein
 3 years ago
Best ResponseYou've already chosen the best response.1second attachment is another ask ?

hosein
 3 years ago
Best ResponseYou've already chosen the best response.1these asks solve with above formulas

hosein
 3 years ago
Best ResponseYou've already chosen the best response.1asks end is magnitude of deflection or path that charge move ? if deflection is right use \[y=0.5(qE/m)t ^{2}\]
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