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hoseinBest ResponseYou've already chosen the best response.1
i think these formulas for that : F=qe &F=ma & this equation :\[y=(1/2)at ^{2}\] if simplify these we have: \[y=(1/2)(qE/m)t ^{2}\] solve this with t=1 E is electric field act on drop
 2 years ago

hoseinBest ResponseYou've already chosen the best response.1
sorry in first formula F=qE not f=qe
 2 years ago

hoseinBest ResponseYou've already chosen the best response.1
first say me by the times means any 1 second?
 2 years ago

hoseinBest ResponseYou've already chosen the best response.1
if no put t=L/V in the y=(1/2)at^2
 2 years ago

hoseinBest ResponseYou've already chosen the best response.1
for m use this\[\rho=m/(4/3\Pi r ^{3})\]
 2 years ago

95123Best ResponseYou've already chosen the best response.0
i used mastering physics and it tell me its wrong
 2 years ago

95123Best ResponseYou've already chosen the best response.0
i have another Q can u help me
 2 years ago

hoseinBest ResponseYou've already chosen the best response.1
i don't solve please wait what's your Q?
 2 years ago

hoseinBest ResponseYou've already chosen the best response.1
ohh this is a another ask am iright?
 2 years ago

hoseinBest ResponseYou've already chosen the best response.1
second attachment is another ask ?
 2 years ago

hoseinBest ResponseYou've already chosen the best response.1
these asks solve with above formulas
 2 years ago

hoseinBest ResponseYou've already chosen the best response.1
asks end is magnitude of deflection or path that charge move ? if deflection is right use \[y=0.5(qE/m)t ^{2}\]
 2 years ago
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