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physics 2 see the photo please and help Me :(

Physics
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this is the Q
1 Attachment
i think these formulas for that : F=qe &F=ma & this equation :\[y=(1/2)at ^{2}\] if simplify these we have: \[y=(1/2)(qE/m)t ^{2}\] solve this with t=1 E is electric field act on drop
sorry in first formula F=qE not f=qe

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Other answers:

why t=1
first say me by the times means any 1 second?
if no put t=L/V in the y=(1/2)at^2
for m use this\[\rho=m/(4/3\Pi r ^{3})\]
did you get it?
wait a minite
sure
not correct
y?
can you explain
i used mastering physics and it tell me its wrong
i have another Q can u help me
i don't solve please wait what's your Q?
this it
1 Attachment
m=3.35*10^-10 right?
wtich one
please see the second Q
ohh this is a another ask am iright?
please help me
second attachment is another ask ?
yes it is another Q
i think x=vt
these asks solve with above formulas
wrong answer
asks end is magnitude of deflection or path that charge move ? if deflection is right use \[y=0.5(qE/m)t ^{2}\]

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