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95123 3 years ago physics 2 see the photo please and help Me :(

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1. 95123

this is the Q

2. hosein

i think these formulas for that : F=qe &F=ma & this equation :$y=(1/2)at ^{2}$ if simplify these we have: $y=(1/2)(qE/m)t ^{2}$ solve this with t=1 E is electric field act on drop

3. hosein

sorry in first formula F=qE not f=qe

4. 95123

why t=1

5. hosein

first say me by the times means any 1 second?

6. hosein

if no put t=L/V in the y=(1/2)at^2

7. hosein

for m use this$\rho=m/(4/3\Pi r ^{3})$

8. hosein

did you get it?

9. 95123

wait a minite

10. hosein

sure

11. 95123

not correct

12. hosein

y?

13. hosein

can you explain

14. 95123

i used mastering physics and it tell me its wrong

15. 95123

i have another Q can u help me

16. hosein

i don't solve please wait what's your Q?

17. 95123

this it

18. hosein

m=3.35*10^-10 right?

19. 95123

wtich one

20. 95123

please see the second Q

21. hosein

ohh this is a another ask am iright?

22. 95123

please help me

23. hosein

second attachment is another ask ?

24. 95123

yes it is another Q

25. hosein

i think x=vt

26. hosein

these asks solve with above formulas

27. 95123

wrong answer

28. hosein

asks end is magnitude of deflection or path that charge move ? if deflection is right use $y=0.5(qE/m)t ^{2}$

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