A community for students. Sign up today!
Here's the question you clicked on:
 0 viewing

This Question is Closed

hosein
 2 years ago
Best ResponseYou've already chosen the best response.1i think these formulas for that : F=qe &F=ma & this equation :\[y=(1/2)at ^{2}\] if simplify these we have: \[y=(1/2)(qE/m)t ^{2}\] solve this with t=1 E is electric field act on drop

hosein
 2 years ago
Best ResponseYou've already chosen the best response.1sorry in first formula F=qE not f=qe

hosein
 2 years ago
Best ResponseYou've already chosen the best response.1first say me by the times means any 1 second?

hosein
 2 years ago
Best ResponseYou've already chosen the best response.1if no put t=L/V in the y=(1/2)at^2

hosein
 2 years ago
Best ResponseYou've already chosen the best response.1for m use this\[\rho=m/(4/3\Pi r ^{3})\]

95123
 2 years ago
Best ResponseYou've already chosen the best response.0i used mastering physics and it tell me its wrong

95123
 2 years ago
Best ResponseYou've already chosen the best response.0i have another Q can u help me

hosein
 2 years ago
Best ResponseYou've already chosen the best response.1i don't solve please wait what's your Q?

hosein
 2 years ago
Best ResponseYou've already chosen the best response.1ohh this is a another ask am iright?

hosein
 2 years ago
Best ResponseYou've already chosen the best response.1second attachment is another ask ?

hosein
 2 years ago
Best ResponseYou've already chosen the best response.1these asks solve with above formulas

hosein
 2 years ago
Best ResponseYou've already chosen the best response.1asks end is magnitude of deflection or path that charge move ? if deflection is right use \[y=0.5(qE/m)t ^{2}\]
Ask your own question
Ask a QuestionFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.