anonymous
  • anonymous
physics 2 see the photo please and help Me :(
Physics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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anonymous
  • anonymous
this is the Q
1 Attachment
anonymous
  • anonymous
i think these formulas for that : F=qe &F=ma & this equation :\[y=(1/2)at ^{2}\] if simplify these we have: \[y=(1/2)(qE/m)t ^{2}\] solve this with t=1 E is electric field act on drop
anonymous
  • anonymous
sorry in first formula F=qE not f=qe

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anonymous
  • anonymous
why t=1
anonymous
  • anonymous
first say me by the times means any 1 second?
anonymous
  • anonymous
if no put t=L/V in the y=(1/2)at^2
anonymous
  • anonymous
for m use this\[\rho=m/(4/3\Pi r ^{3})\]
anonymous
  • anonymous
did you get it?
anonymous
  • anonymous
wait a minite
anonymous
  • anonymous
sure
anonymous
  • anonymous
not correct
anonymous
  • anonymous
y?
anonymous
  • anonymous
can you explain
anonymous
  • anonymous
i used mastering physics and it tell me its wrong
anonymous
  • anonymous
i have another Q can u help me
anonymous
  • anonymous
i don't solve please wait what's your Q?
anonymous
  • anonymous
this it
1 Attachment
anonymous
  • anonymous
m=3.35*10^-10 right?
anonymous
  • anonymous
wtich one
anonymous
  • anonymous
please see the second Q
anonymous
  • anonymous
ohh this is a another ask am iright?
anonymous
  • anonymous
please help me
anonymous
  • anonymous
second attachment is another ask ?
anonymous
  • anonymous
yes it is another Q
anonymous
  • anonymous
i think x=vt
anonymous
  • anonymous
these asks solve with above formulas
anonymous
  • anonymous
wrong answer
anonymous
  • anonymous
asks end is magnitude of deflection or path that charge move ? if deflection is right use \[y=0.5(qE/m)t ^{2}\]

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