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anonymous 4 years ago What would be the resulting molarity of a solution made by dissolving 17.8 grams of LiF in enough water to make a 915-milliliter solution? Show all of the work needed to solve this problem.

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1. Rogue

$Molarity = \frac {moles solute}{volume solution}$$M = \frac {n}{v}$$17.8 g LiF * \frac {1 mole LiF}{25.939 g LiF} = 0.686 mol LiF$$915 mL * \frac {1 L}{1000 mL} = 0.915 L$$M = \frac {0.686 mol LiF}{0.915 L} = 0.750M$

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