anonymous
  • anonymous
Essay: Show all work. Find the following quotient: 25x^2-100y^2/5x+10y
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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anonymous
  • anonymous
Difference of 2 squares in the numerator, can you factor those?
anonymous
  • anonymous
what do you mean
anonymous
  • anonymous
\[a^2-b^2=(a-b)(a+b)\]

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More answers

anonymous
  • anonymous
look familiar?
anonymous
  • anonymous
yes but i never know how to plug the numbers in
anonymous
  • anonymous
what is\[\sqrt{25x^2}\]
anonymous
  • anonymous
5x^2
anonymous
  • anonymous
close
anonymous
  • anonymous
what is\[\sqrt{x^2}\]
anonymous
  • anonymous
x^1.41
anonymous
  • anonymous
\[\sqrt{x^2}=x\]
anonymous
  • anonymous
can you explain that rick? and then retrice natz the original question?
anonymous
  • anonymous
weird bug, ask natz*
anonymous
  • anonymous
huh dgo
anonymous
  • anonymous
i typed a s s k i think
anonymous
  • anonymous
anyhow I am wondering what you are taking away from all the answers youve been getting. are you learning how to do this stuff?
anonymous
  • anonymous
yes i have learned a lot from this website i just have a hard time grasping it .It takes me to learn it mre than once before i got it all the way
anonymous
  • anonymous
your answer is 5x-10y use difference of squares to simplify into: \[(5x+10y)(5x-10y)\div(5x+10y)\] (5x+10y) crosses out from the equation because \[(5x+10y)\div(5x+10y)=1\] so you are left with 5x-10y
anonymous
  • anonymous
same for me natz haha ive learned a lot from this website, just takes me so long
anonymous
  • anonymous
it is just math is my worst subject
anonymous
  • anonymous
addrigonzalez is that the whole problem
anonymous
  • anonymous
do you understand adri's answer?
anonymous
  • anonymous
it should be, you are looking for a quotient, right? so if 6 is divided by 3, the quotient is 2
anonymous
  • anonymous
yes they cross out eachother
anonymous
  • anonymous
i love math, we are on derivatives in college and i just dont understand my foreign teacher or whay we even need derivatives in the first place
anonymous
  • anonymous
derivatives are unnessecary

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