anonymous
  • anonymous
How do I solve 8cos x = (sec x)^2?
Mathematics
schrodinger
  • schrodinger
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anonymous
  • anonymous
sec^2x = 1/cos^2x
anonymous
  • anonymous
8cos^3x=0
anonymous
  • anonymous
cos(pi/2) = 0

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anonymous
  • anonymous
so 8cos^3(pi/2)=0
anonymous
  • anonymous
I got lost on the first step.. Sorry, can you explain it more?
anonymous
  • anonymous
sure, first you need to memorize all of the identitites memorize : sec(x) = 1/cos(x)
anonymous
  • anonymous
whoa whoa whoa, \[8\cos^2(x) = 1\] not zero...
anonymous
  • anonymous
so sec^2(x) = 1/cos^2(x)
anonymous
  • anonymous
ah right 1 my bad
anonymous
  • anonymous
|dw:1329118155688:dw| So like this?
anonymous
  • anonymous
anyway multiply across so 1/cos^2(x) * cos^2(x) = cos^2(x) * 8cos(x)
anonymous
  • anonymous
1 = 8cos^3(x)
anonymous
  • anonymous
Ohh I see. Thank you.
anonymous
  • anonymous
So it would be x = pi/3 instead of pi/2 right?

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