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ns36

  • 4 years ago

Find the volume of the described solid S: the base of S is a circular disk with radius r. Parallel cross-sections perpendicular to the base are squares.

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  1. dumbcow
    • 4 years ago
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    |dw:1329557645302:dw| Due to symmetry we can integrate from 0 to r and just double the integral \[V = 2\int\limits_{0}^{r}A(x) dx\] \[V = 8\int\limits_{0}^{r}(r^{2}-x^{2}) dx\] \[8 | r^{2}x - x^{3}/3 = 8(r^{3} - r^{3}/3) = \frac{16}{3}r^{3}\]

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