A community for students. Sign up today!
Here's the question you clicked on:
 0 viewing
 2 years ago
Write an equation for the problem and solve.
There are 17 2/3 gallons of water in the tank. The tank is 3/4 full. How many gallons of water, G, can the tank hold?
My answer was G= 13 1/4. I did the inverse and got 17 2/3 gallons back that's correct.. But why is it that the tank holds less the the amount currently in it... Where did I go wrong.
 2 years ago
Write an equation for the problem and solve. There are 17 2/3 gallons of water in the tank. The tank is 3/4 full. How many gallons of water, G, can the tank hold? My answer was G= 13 1/4. I did the inverse and got 17 2/3 gallons back that's correct.. But why is it that the tank holds less the the amount currently in it... Where did I go wrong.

This Question is Closed

agbyoung
 2 years ago
Best ResponseYou've already chosen the best response.0Mertsj, I am trying to figure out where did I go wrong finding G or in your case X

Mertsj
 2 years ago
Best ResponseYou've already chosen the best response.1\[x=\frac{53}{3}\times\frac{4}{3}=\frac{212}{9}\]

Mertsj
 2 years ago
Best ResponseYou've already chosen the best response.1What equation did you write?

Mertsj
 2 years ago
Best ResponseYou've already chosen the best response.1The thought process is; 3/4 of a full tank is 17 2/3

agbyoung
 2 years ago
Best ResponseYou've already chosen the best response.0\[\alpha \times 3/4= \]

DougBaden
 2 years ago
Best ResponseYou've already chosen the best response.0The amount the tank can hold should have been 23.55. \[(3/4) t = 17.66\] \[(1/4) t = (17.66)/4\] \[t = 17.666 *(4/3)\] \[t = 17.55\]
Ask your own question
Ask a QuestionFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.