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3/4x=17 2/3

Mertsj, I am trying to figure out where did I go wrong finding G or in your case X

\[x=\frac{53}{3}\times\frac{4}{3}=\frac{212}{9}\]

What equation did you write?

The thought process is; 3/4 of a full tank is 17 2/3

\[\alpha \times 3/4= \]

METSj Thanks!!

yw