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anonymous
 4 years ago
whats the direction of electric field on q
anonymous
 4 years ago
whats the direction of electric field on q

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anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0dw:1329405754471:dw

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0and... please tell methe rules too... D: the direction is confusing

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0I don't understand those symbols :O

ash2326
 4 years ago
Best ResponseYou've already chosen the best response.1shininigami electric field 's direction is away from a positive charge, and towards a negative charge.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0dw:1329406138267:dw

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0this is the case if BOTH CHARGES ARE POSITIVE.. and their magnitudes almost same..

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0but my answer key says like this....

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0dw:1329406244978:dw

ash2326
 4 years ago
Best ResponseYou've already chosen the best response.1yeah, it's because we have to show only the horizontal field, all are positive, and if q2>q>q1, then this will be the answer

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0is it from left to right or it should be from largest to biggest??

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0sorry.. direction of electric field on Q? :D!!.. i just drew lines of force!!..

ash2326
 4 years ago
Best ResponseYou've already chosen the best response.1dw:1329406488894:dwsee from a positive charge field should originate if there are two positive charges in a line, then charge will originate from both, here q2 and q1 are positive

ash2326
 4 years ago
Best ResponseYou've already chosen the best response.1dw:1329406677857:dwif q2> q1 => field due to q2 (E2) > field due to q1 (E1) so in between them, the fields are opposite effective field between them = E2 E1 int he direction shown

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0i think i;m getting this... hahah since q is only a test charge... i think i can deny its quantity

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0actually your question doesn't make sense.. direction of electric field ON q!??!?!? ..
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