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Oh! that thing, I am afraid you will have to figure that out yourself.

But the key is to practice more and more reduction..

myself????? :O I've tried to...but i don't get it :((((

ok....can u explain me how u solve aproblem like this in twiddla??

Why not here..?

yea ok ....

So will I post an example? Or you will post yours

I'll post one |dw:1329561659776:dw|

OK, now tell me what do you feel you must first do, and why?

I have no idea at all :(((

OK, now you have to reduce it to something like |dw:1329561739686:dw|

With zeros in all the empty spaces, right?

yea tht's smth i know...

So start by making the top left corner 1

You can do that by two methods,
1. Bring the lowest row to the top,
2. Divide the first column by 3

The first method seems easy

I just exchanged row 1, and row 3

now u have to make 4 in the 3rd row 1 right?

Oh no, there is another, just let me write it fresh...

what happened to the 2 at the right corner?

|dw:1329562219705:dw|

|dw:1329562156101:dw|

Right!

Now again think, to make this new matrix similar to |dw:1329562260442:dw|

.....you need to make the first element in the 2nd row zero.

i think u'll get a |dw:1329562374039:dw| won't you???

i.e. the circled element |dw:1329562329966:dw|

Sorry, you lost me.. but did you understand what I meant?

yea yea i understood xD
just tell me smth u make a diagonal =1 first and then 0 the other elements??

Right!

So the next step would be to subtract 2 times row-1 from row-2. Could you follow me?

I mean do you feel why I am doing that?

no.....don't u have to make the 4 in the third row 0 first???? O.o

Which one? Can you circle it for me?

|dw:1329562705396:dw|

No, not at all. All you need to do is keep in mind the picture I gave you and proceed accordingly

By picture I meant, the matrix with 1 on the diagonals and 0s elsewhere.

I mean after reduction your picture will look something like that funny picture.

Just to make it look like that funny picture...

You will end up with something like
|dw:1329563098194:dw|

tht's wht i meant by this pic |dw:1329563199692:dw|

I really don't understand that notation of yours, but do you understand mine?

;)

hahhaha...yea yea xD

So just tell me, do you feel why I want to make the element just below 1, zero?

i mean the diagonal that must be all 1's....

Any diagonal...

Well, I never learnt it that way...:)

May be that is some other method.

ahhhhaaaaaaaaaa...ok then...u do wht u know...:)

math is a very clumsy road, u end up at the same destination

i wasn't ending up anywhere with this problem :P

did u read the manual/instruction/algorithm to solving this problem?

|dw:1329563439879:dw|

Is that clear?

wht did u do in there?????

OMG!!! I'm hopeless x( :(:(

R2-2R1

got it or not?

wasn't the first element of the 2nd row supposed to b zero???
2-(2*1)=2-2=0

Oh, does that thing look like 6, its actually 0..

lol

ahhhhaaaaa...ok then xD

Next you need to turn the first element in the third row equal to zero

would tht be R3-3R1???

wait so u do 1 0 0 column by column, as in one column after the other?

|dw:1329563860051:dw|

Sasogeek is right!

1000
0100
0010
u should end up with this... right?

ok....no now u have to make -3 in the 2nd column zero...how do u do tht???

First of all, can you check, if I did the calculations correct?

hang on

|dw:1329564323164:dw|

Thats right! I think

i think so too O.o.....wht's next?

So the matrix which we now have is |dw:1329564404847:dw|

But that is a nice case, it will not happen always.

Once the circle element is made 1, you will attempt to make all the elements below it equal to 0

can we multiply the second row with 1/7???

Yes, that is exactly what you should have done if you were a computer.

can.. but it would be complicated

try avoiding fractions form..

then what?? O.o

And that will make the whole of third row equal to zero

ohhhhhh...well i'm not a random person...I think like a computer :P

|dw:1329564788814:dw|

7 is still 7...wht now?

So now clearly you have two non zero rows, you can now say, that the range is 2

R3=R3+R2

:O wht??? how was tht ..can u explain me once again please ???

ops it is R3=R3-R2

i dont understand what is range?

Here is a good problem

i don't think it is good :P

I meant it gives you the feel of what you need to do in real problems

ok now i understad what is range.. :)

And you can see in the reduction, things go in the same algorithm as I mentioned

so for the attachement given.. the range is 3 right?

Right xilem

ok now i understand.. but what it is for?

Something very deep xilem, its for actually solving linear equation.

yea...why do we need these kind of problems in business? O.o

But now it seems like a game

Say I have 10 equations and each equations have 10 unknown, how are you going to solve it?

crammer's rule :D

But how did crammer invent that? This is all behind the scenes

i think all these things r unnecessary.....

I'm going to do my hws now...hopefully i'll solve them :) thnx a lot :)

hurmm... sorry can u show me example of that in cramers rule?

this is how I've been taught cramer's rule |dw:1329576915751:dw|