A community for students.
Here's the question you clicked on:
 0 viewing
adnanchowdhury
 3 years ago
How many different numbers can be formed by taking one, two, three and four digits from the digits 1, 2, 7 and 8, if repetition are not allowed?
adnanchowdhury
 3 years ago
How many different numbers can be formed by taking one, two, three and four digits from the digits 1, 2, 7 and 8, if repetition are not allowed?

This Question is Closed

bahrom7893
 3 years ago
Best ResponseYou've already chosen the best response.11 digit  4 ways (any one can be chosen)

bahrom7893
 3 years ago
Best ResponseYou've already chosen the best response.12  digits  4*3 ways (you picked the first one, so now you have 3 to choose from)

bahrom7893
 3 years ago
Best ResponseYou've already chosen the best response.1Waaait, isn't it 4C1

adnanchowdhury
 3 years ago
Best ResponseYou've already chosen the best response.0I don't understand. Can you list the permutations? I can't seem to understand what the question is saying.

adnanchowdhury
 3 years ago
Best ResponseYou've already chosen the best response.0Answer is supposed to be 64.

bahrom7893
 3 years ago
Best ResponseYou've already chosen the best response.1wait im wrong.. hold up. You have to use that formula, like the number of ways of choosing some object from a set of objects with no repetitions

bahrom7893
 3 years ago
Best ResponseYou've already chosen the best response.1ehhh... im lost.. crap i suck at probability

adnanchowdhury
 3 years ago
Best ResponseYou've already chosen the best response.0Can you explain what the question is asking? What does it mean when it says: 'take one, two, three and four digits from the digits 1, 2, 7 and 8'?

bahrom7893
 3 years ago
Best ResponseYou've already chosen the best response.1im thinking: Pick one digit from 1,2,7 and 8. Like I can pick 1, or 2, or 7, or 8, so the answer's 4 ways

adnanchowdhury
 3 years ago
Best ResponseYou've already chosen the best response.0So would one possibility be 1278?

adnanchowdhury
 3 years ago
Best ResponseYou've already chosen the best response.0One digit possibilities: 1, 2, 7 and 8. So there are 4 permutations for one digits...?

adnanchowdhury
 3 years ago
Best ResponseYou've already chosen the best response.0I understand now!

adnanchowdhury
 3 years ago
Best ResponseYou've already chosen the best response.04 possibilities for 1 digits. 4x3 = 12 possibilities for 2 digits. And so on..

bahrom7893
 3 years ago
Best ResponseYou've already chosen the best response.1yes that's what i was trying to say adnan

adnanchowdhury
 3 years ago
Best ResponseYou've already chosen the best response.0Thanks! My problem was in understanding what the question was asking, but after you explained it, i understood.

amistre64
 3 years ago
Best ResponseYou've already chosen the best response.21, 2, 7 and 8 1 digit numbers; there are only 4 numbers so: 4 2 digit number: 12 17 18; 4 times = 12; 4P1 * 3P1 = 12 3digit number: 127 128 172 178 182 187; 6*4 = 24; 4*3*2 = 24 4 digit numbers: 1278 1287 1728 1782 1827 1872: 6*4 = 24; 4*3*2*1 = 24 4+12+24+24 = 4+12(3) = 40 i beleive

amistre64
 3 years ago
Best ResponseYou've already chosen the best response.2lol, almost had that right

amistre64
 3 years ago
Best ResponseYou've already chosen the best response.260+4 if i learn to count :)

adnanchowdhury
 3 years ago
Best ResponseYou've already chosen the best response.0Any formula i could have used to save me time?

amistre64
 3 years ago
Best ResponseYou've already chosen the best response.2not really; since it is split up into 4 groups to count individually you still have a bit of work

amistre64
 3 years ago
Best ResponseYou've already chosen the best response.2knowing the cPr stuff helps tho

adnanchowdhury
 3 years ago
Best ResponseYou've already chosen the best response.0I understood the formula before. But now, I just find it confusing.

amistre64
 3 years ago
Best ResponseYou've already chosen the best response.2yeah, its just a "structured" way to count and if you dont use it you tend to go back to the basic method of 1,2,3,4,5s

adnanchowdhury
 3 years ago
Best ResponseYou've already chosen the best response.0I see. I work it out intuitively now  probably takes me a bit longer, but i get there eventually.
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.