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anonymous
 4 years ago
Gravel is dropped on a conveyor belt at the rate of 0.5kg/s. The extra force in Newton required to keep the belt moving at 2m/s, is
anonymous
 4 years ago
Gravel is dropped on a conveyor belt at the rate of 0.5kg/s. The extra force in Newton required to keep the belt moving at 2m/s, is

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anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0are you asking 2 or 0.5?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Is it 2 metre/second na?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0It's one of the option

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0which one? please do say the options.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0(a) 1N (b) 2N (c) 4N (d) 0.5 N

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0What I think is the conveyor belt is initially at rest. Gravel mass is 0.5 kg. Now given velocity is 2 m / s. So just multiplied using the force formula.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0It is, but you need a reason behind it :D

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0I request others to check and criticize me if I am wrong.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0force=momentum*time so momentum is given for unit time (1 second) determine it

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0So even my answer is correct I believe.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0the force is nevertheless 0.5N no matter how u speed up

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Momentum is mass*velocity

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Abdul, What is the correct option given in the key?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0sry i dint read the question properly so yes first find momentum and then force

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0This was given in FIITJEE

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0I could know that. U can even find such questions in BMA workbook.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Yeah. Its actually 9th portion. Still u can try.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Write the net force as: \[\ F_{net}= F  F_{thrust} \] it is F_thurst because the mass in increasing The net force is zero because the system is not increasing or decreasing its velocity, that is the velocity is constant. Now, \[\ F_{thrust}=v\frac{dm}{dt}\] I think it is fairly easy to solve it now :D.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Yeah. so my answer is correct.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0change in mass per unit time or how much mass is added per second.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Even I will know the use of "d" in formulae in 11th grade. Can anyone explain it in detail?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0d is a symbol for a differential. It represents an infitesimal change of some quantity (you will get to that in calculus). It's like \[\ \Delta \] but infinitely small.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0So, its a very tough concept. What about Calculus? I just know 2 words  Integration and Differentiation.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Yes that's what you do in Calculus :D. If you are impatient to learn about it I would recommend "Calculus" by Gilbert Strang Link: http://ocw.mit.edu/ans7870/resources/Strang/Edited/Calculus/Calculus.pdf
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