Open study

is now brainly

With Brainly you can:

  • Get homework help from millions of students and moderators
  • Learn how to solve problems with step-by-step explanations
  • Share your knowledge and earn points by helping other students
  • Learn anywhere, anytime with the Brainly app!

A community for students.

Gravel is dropped on a conveyor belt at the rate of 0.5kg/s. The extra force in Newton required to keep the belt moving at 2m/s, is

See more answers at
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly


Get your free account and access expert answers to this and thousands of other questions

Is it 2/0.5?
I am not sure.
are you asking 2 or 0.5?

Not the answer you are looking for?

Search for more explanations.

Ask your own question

Other answers:

Is it 2 metre/second na?
It's one of the option
which one? please do say the options.
(a) 1N (b) 2N (c) 4N (d) 0.5 N
I think 2 * 0.5 = 1.
Can you explain it?
What I think is the conveyor belt is initially at rest. Gravel mass is 0.5 kg. Now given velocity is 2 m / s. So just multiplied using the force formula.
It is, but you need a reason behind it :D
I request others to check and criticize me if I am wrong.
force=momentum*time so momentum is given for unit time (1 second) determine it
So even my answer is correct I believe.
the force is nevertheless 0.5N no matter how u speed up
Momentum is mass*velocity
But How?
Abdul, What is the correct option given in the key?
Key was not given
sry i dint read the question properly so yes first find momentum and then force
This was given in FIITJEE
I could know that. U can even find such questions in BMA workbook.
In 8th?
Yeah. Its actually 9th portion. Still u can try.
Write the net force as: \[\ F_{net}= F - F_{thrust} \] it is -F_thurst because the mass in increasing The net force is zero because the system is not increasing or decreasing its velocity, that is the velocity is constant. Now, \[\ F_{thrust}=v\frac{dm}{dt}\] I think it is fairly easy to solve it now :D.
Yeah. so my answer is correct.
What is dm/dt?
change in mass per unit time or how much mass is added per second.
Even I will know the use of "d" in formulae in 11th grade. Can anyone explain it in detail?
d is a symbol for a differential. It represents an infitesimal change of some quantity (you will get to that in calculus). It's like \[\ \Delta \] but infinitely small.
So, its a very tough concept. What about Calculus? I just know 2 words - Integration and Differentiation.
Yes that's what you do in Calculus :D. If you are impatient to learn about it I would recommend "Calculus" by Gilbert Strang Link:

Not the answer you are looking for?

Search for more explanations.

Ask your own question