Gravel is dropped on a conveyor belt at the rate of 0.5kg/s. The extra force in Newton required to keep the belt moving at 2m/s, is

- anonymous

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- anonymous

Is it 2/0.5?

- anonymous

I am not sure.

- anonymous

are you asking 2 or 0.5?

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## More answers

- anonymous

Is it 2 metre/second na?

- anonymous

It's one of the option

- anonymous

which one? please do say the options.

- anonymous

(a) 1N
(b) 2N
(c) 4N
(d) 0.5 N

- anonymous

I think 2 * 0.5 = 1.

- anonymous

Can you explain it?

- anonymous

What I think is the conveyor belt is initially at rest. Gravel mass is 0.5 kg. Now given velocity is 2 m / s. So just multiplied using the force formula.

- anonymous

It is, but you need a reason behind it :D

- anonymous

I request others to check and criticize me if I am wrong.

- anonymous

force=momentum*time
so momentum is given for unit time (1 second) determine it

- anonymous

So even my answer is correct I believe.

- anonymous

the force is nevertheless 0.5N no matter how u speed up

- anonymous

Momentum is mass*velocity

- anonymous

But How?

- anonymous

Abdul, What is the correct option given in the key?

- anonymous

Key was not given

- anonymous

Oooooooooooooooo

- anonymous

sry i dint read the question properly so yes
first find momentum and then force

- anonymous

This was given in FIITJEE

- anonymous

I could know that. U can even find such questions in BMA workbook.

- anonymous

In 8th?

- anonymous

Yeah. Its actually 9th portion. Still u can try.

- anonymous

Write the net force as:
\[\ F_{net}= F - F_{thrust} \]
it is -F_thurst because the mass in increasing
The net force is zero because the system is not increasing or decreasing its velocity, that is the velocity is constant.
Now, \[\ F_{thrust}=v\frac{dm}{dt}\]
I think it is fairly easy to solve it now :D.

- anonymous

Yeah. so my answer is correct.

- anonymous

What is dm/dt?

- anonymous

change in mass per unit time or how much mass is added per second.

- anonymous

Even I will know the use of "d" in formulae in 11th grade. Can anyone explain it in detail?

- anonymous

d is a symbol for a differential. It represents an infitesimal change of some quantity (you will get to that in calculus).
It's like \[\ \Delta \] but infinitely small.

- anonymous

So, its a very tough concept. What about Calculus? I just know 2 words - Integration and Differentiation.

- anonymous

Yes that's what you do in Calculus :D. If you are impatient to learn about it I would recommend "Calculus" by Gilbert Strang
Link: http://ocw.mit.edu/ans7870/resources/Strang/Edited/Calculus/Calculus.pdf

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