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abdul_shabeer
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Gravel is dropped on a conveyor belt at the rate of 0.5kg/s. The extra force in Newton required to keep the belt moving at 2m/s, is
 2 years ago
 2 years ago
abdul_shabeer Group Title
Gravel is dropped on a conveyor belt at the rate of 0.5kg/s. The extra force in Newton required to keep the belt moving at 2m/s, is
 2 years ago
 2 years ago

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Aadarsh Group TitleBest ResponseYou've already chosen the best response.0
Is it 2/0.5?
 2 years ago

Aadarsh Group TitleBest ResponseYou've already chosen the best response.0
I am not sure.
 2 years ago

abdul_shabeer Group TitleBest ResponseYou've already chosen the best response.0
are you asking 2 or 0.5?
 2 years ago

Aadarsh Group TitleBest ResponseYou've already chosen the best response.0
Is it 2 metre/second na?
 2 years ago

abdul_shabeer Group TitleBest ResponseYou've already chosen the best response.0
It's one of the option
 2 years ago

Aadarsh Group TitleBest ResponseYou've already chosen the best response.0
which one? please do say the options.
 2 years ago

abdul_shabeer Group TitleBest ResponseYou've already chosen the best response.0
(a) 1N (b) 2N (c) 4N (d) 0.5 N
 2 years ago

Aadarsh Group TitleBest ResponseYou've already chosen the best response.0
I think 2 * 0.5 = 1.
 2 years ago

abdul_shabeer Group TitleBest ResponseYou've already chosen the best response.0
Can you explain it?
 2 years ago

Aadarsh Group TitleBest ResponseYou've already chosen the best response.0
What I think is the conveyor belt is initially at rest. Gravel mass is 0.5 kg. Now given velocity is 2 m / s. So just multiplied using the force formula.
 2 years ago

gogind Group TitleBest ResponseYou've already chosen the best response.3
It is, but you need a reason behind it :D
 2 years ago

Aadarsh Group TitleBest ResponseYou've already chosen the best response.0
I request others to check and criticize me if I am wrong.
 2 years ago

salini Group TitleBest ResponseYou've already chosen the best response.0
force=momentum*time so momentum is given for unit time (1 second) determine it
 2 years ago

Aadarsh Group TitleBest ResponseYou've already chosen the best response.0
So even my answer is correct I believe.
 2 years ago

salini Group TitleBest ResponseYou've already chosen the best response.0
the force is nevertheless 0.5N no matter how u speed up
 2 years ago

abdul_shabeer Group TitleBest ResponseYou've already chosen the best response.0
Momentum is mass*velocity
 2 years ago

Aadarsh Group TitleBest ResponseYou've already chosen the best response.0
Abdul, What is the correct option given in the key?
 2 years ago

abdul_shabeer Group TitleBest ResponseYou've already chosen the best response.0
Key was not given
 2 years ago

Aadarsh Group TitleBest ResponseYou've already chosen the best response.0
Oooooooooooooooo
 2 years ago

salini Group TitleBest ResponseYou've already chosen the best response.0
sry i dint read the question properly so yes first find momentum and then force
 2 years ago

abdul_shabeer Group TitleBest ResponseYou've already chosen the best response.0
This was given in FIITJEE
 2 years ago

Aadarsh Group TitleBest ResponseYou've already chosen the best response.0
I could know that. U can even find such questions in BMA workbook.
 2 years ago

abdul_shabeer Group TitleBest ResponseYou've already chosen the best response.0
In 8th?
 2 years ago

Aadarsh Group TitleBest ResponseYou've already chosen the best response.0
Yeah. Its actually 9th portion. Still u can try.
 2 years ago

gogind Group TitleBest ResponseYou've already chosen the best response.3
Write the net force as: \[\ F_{net}= F  F_{thrust} \] it is F_thurst because the mass in increasing The net force is zero because the system is not increasing or decreasing its velocity, that is the velocity is constant. Now, \[\ F_{thrust}=v\frac{dm}{dt}\] I think it is fairly easy to solve it now :D.
 2 years ago

Aadarsh Group TitleBest ResponseYou've already chosen the best response.0
Yeah. so my answer is correct.
 2 years ago

abdul_shabeer Group TitleBest ResponseYou've already chosen the best response.0
What is dm/dt?
 2 years ago

gogind Group TitleBest ResponseYou've already chosen the best response.3
change in mass per unit time or how much mass is added per second.
 2 years ago

Aadarsh Group TitleBest ResponseYou've already chosen the best response.0
Even I will know the use of "d" in formulae in 11th grade. Can anyone explain it in detail?
 2 years ago

gogind Group TitleBest ResponseYou've already chosen the best response.3
d is a symbol for a differential. It represents an infitesimal change of some quantity (you will get to that in calculus). It's like \[\ \Delta \] but infinitely small.
 2 years ago

Aadarsh Group TitleBest ResponseYou've already chosen the best response.0
So, its a very tough concept. What about Calculus? I just know 2 words  Integration and Differentiation.
 2 years ago

gogind Group TitleBest ResponseYou've already chosen the best response.3
Yes that's what you do in Calculus :D. If you are impatient to learn about it I would recommend "Calculus" by Gilbert Strang Link: http://ocw.mit.edu/ans7870/resources/Strang/Edited/Calculus/Calculus.pdf
 2 years ago
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