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ammy1234

  • 4 years ago

Brenda made two similar glass display boxes shaped like triangular prisms. The length of the sides of the base of the first display box is 4 feet, and the length of the sides of the base of the second display box is 8 feet. If the volume of the first display box is 42 ft3, what is the volume of the second display box?

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  1. amistre64
    • 4 years ago
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    4^2 sin(60) ---------- = base triangle area i believe 2

  2. amistre64
    • 4 years ago
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    |dw:1329592783061:dw| base = sqrt(3) sqrt(3) * h = 42 h = 42/sqrt(3) , is that right?

  3. ammy1234
    • 4 years ago
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    336 ft3 672 ft3 1344 ft3 2688 ft3

  4. ammy1234
    • 4 years ago
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    is the choices

  5. amistre64
    • 4 years ago
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    then with any luck we will arrive at one of those choices :)

  6. ammy1234
    • 4 years ago
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    ok lets do it

  7. amistre64
    • 4 years ago
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    |dw:1329592905817:dw| 4*4 sin(60) ---------- = base area 2 4*4*sqrt(3) --------- = 4sqrt(3) for the base area 4 4sqrt(3) * h = 42 h = 21/2sqrt(3)

  8. amistre64
    • 4 years ago
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    if we double this to be similar to the other one in measure we get a height of 21/sqrt(3)

  9. amistre64
    • 4 years ago
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    base area of other one is: 8*8 sin(60) 8*8*sqrt(3) ---------- = ---------- = 16 sqrt(3) 2 4 16sqrt(3) * 21/sqrt(3) = 16*21 ... 210 +126 = 336 ... maybe?

  10. amistre64
    • 4 years ago
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    yay!! its an option, if its right or not tho ... lol

  11. ammy1234
    • 4 years ago
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    good enough for me haha thanks

  12. amistre64
    • 4 years ago
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    yw, i cant see any fauxpauxes in my work so it might be good; at least an 83% chance of success lol

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