## anonymous 4 years ago Anyone Know how to do this kind of work that will help me through these problems would be really helpful!!!!!!!! 7( x - 1 ) ≥ -14

1. anonymous

divide by 7 get $x-1\geq -2$ then add 1 to both sides to get $x\geq -1$

2. saifoo.khan

$x-1 \ge - \frac{14}{7}$ $x-1 \ge - 2$ Add 1 on both sides, $x \ge -2 +1$ $x \ge Answer$

3. anonymous

-3( x - 4 ) - 2( x + 4) ≤ 9

4. anonymous

7x-7>=-14; 7x>=-14+7; x>=-7/7; x>=-1

5. anonymous

-3( x - 4 ) - 2( x + 4) ≤ 9

6. anonymous

$x\geq -1$ as before

7. anonymous

5( x + 1) - 3( x - 1) > -9

8. anonymous

$x\geq -\frac{17}{2}$

9. anonymous

-3x+12-2x-8=<-9; -5x+4=<-9; -5x=<-4-9; -5x=<-13; (x-1) x>=13/5

10. anonymous

4(x + 3) > 6(x - 5)

11. anonymous

4x+12>6x-30; 4x-6x>-30-12; -2x>-42 (x-1) x<42/2; x<21

12. anonymous

x -1 >= -2 ->x >= -1

13. anonymous

3x + 5 < 5

14. anonymous

In general you want to approach inequalities the same way that you would a simple equality however when you multiply or divide by a negative then you must change the direction of the inequality. i.e.) -x > 5 becomes x < 5.

15. anonymous

ok for 3x+ 5< 5 I got x ≥ -3 is that right ?

16. anonymous

sorry -5(x + 3) ≥ 0 I got x ≥ -3