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miababygirl1987

  • 3 years ago

Anyone Know how to do this kind of work that will help me through these problems would be really helpful!!!!!!!! 7( x - 1 ) ≥ -14

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  1. satellite73
    • 3 years ago
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    divide by 7 get \[x-1\geq -2\] then add 1 to both sides to get \[x\geq -1\]

  2. saifoo.khan
    • 3 years ago
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    \[x-1 \ge - \frac{14}{7}\] \[x-1 \ge - 2\] Add 1 on both sides, \[x \ge -2 +1\] \[x \ge Answer\]

  3. miababygirl1987
    • 3 years ago
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    -3( x - 4 ) - 2( x + 4) ≤ 9

  4. viniterranova
    • 3 years ago
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    7x-7>=-14; 7x>=-14+7; x>=-7/7; x>=-1

  5. miababygirl1987
    • 3 years ago
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    -3( x - 4 ) - 2( x + 4) ≤ 9

  6. satellite73
    • 3 years ago
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    \[x\geq -1\] as before

  7. miababygirl1987
    • 3 years ago
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    5( x + 1) - 3( x - 1) > -9

  8. satellite73
    • 3 years ago
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    \[x\geq -\frac{17}{2}\]

  9. viniterranova
    • 3 years ago
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    -3x+12-2x-8=<-9; -5x+4=<-9; -5x=<-4-9; -5x=<-13; (x-1) x>=13/5

  10. miababygirl1987
    • 3 years ago
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    4(x + 3) > 6(x - 5)

  11. viniterranova
    • 3 years ago
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    4x+12>6x-30; 4x-6x>-30-12; -2x>-42 (x-1) x<42/2; x<21

  12. Chlorophyll
    • 3 years ago
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    x -1 >= -2 ->x >= -1

  13. miababygirl1987
    • 3 years ago
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    3x + 5 < 5

  14. Wolf77
    • 3 years ago
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    In general you want to approach inequalities the same way that you would a simple equality however when you multiply or divide by a negative then you must change the direction of the inequality. i.e.) -x > 5 becomes x < 5.

  15. miababygirl1987
    • 3 years ago
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    ok for 3x+ 5< 5 I got x ≥ -3 is that right ?

  16. miababygirl1987
    • 3 years ago
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    sorry -5(x + 3) ≥ 0 I got x ≥ -3

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