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Anyone Know how to do this kind of work that will help me through these problems would be really helpful!!!!!!!! 7( x - 1 ) ≥ -14

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divide by 7 get \[x-1\geq -2\] then add 1 to both sides to get \[x\geq -1\]
\[x-1 \ge - \frac{14}{7}\] \[x-1 \ge - 2\] Add 1 on both sides, \[x \ge -2 +1\] \[x \ge Answer\]
-3( x - 4 ) - 2( x + 4) ≤ 9

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Other answers:

7x-7>=-14; 7x>=-14+7; x>=-7/7; x>=-1
-3( x - 4 ) - 2( x + 4) ≤ 9
\[x\geq -1\] as before
5( x + 1) - 3( x - 1) > -9
\[x\geq -\frac{17}{2}\]
-3x+12-2x-8=<-9; -5x+4=<-9; -5x=<-4-9; -5x=<-13; (x-1) x>=13/5
4(x + 3) > 6(x - 5)
4x+12>6x-30; 4x-6x>-30-12; -2x>-42 (x-1) x<42/2; x<21
x -1 >= -2 ->x >= -1
3x + 5 < 5
In general you want to approach inequalities the same way that you would a simple equality however when you multiply or divide by a negative then you must change the direction of the inequality. i.e.) -x > 5 becomes x < 5.
ok for 3x+ 5< 5 I got x ≥ -3 is that right ?
sorry -5(x + 3) ≥ 0 I got x ≥ -3

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