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miababygirl1987 Group Title

Anyone Know how to do this kind of work that will help me through these problems would be really helpful!!!!!!!! 7( x - 1 ) ≥ -14

  • 2 years ago
  • 2 years ago

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  1. satellite73 Group Title
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    divide by 7 get \[x-1\geq -2\] then add 1 to both sides to get \[x\geq -1\]

    • 2 years ago
  2. saifoo.khan Group Title
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    \[x-1 \ge - \frac{14}{7}\] \[x-1 \ge - 2\] Add 1 on both sides, \[x \ge -2 +1\] \[x \ge Answer\]

    • 2 years ago
  3. miababygirl1987 Group Title
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    -3( x - 4 ) - 2( x + 4) ≤ 9

    • 2 years ago
  4. viniterranova Group Title
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    7x-7>=-14; 7x>=-14+7; x>=-7/7; x>=-1

    • 2 years ago
  5. miababygirl1987 Group Title
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    -3( x - 4 ) - 2( x + 4) ≤ 9

    • 2 years ago
  6. satellite73 Group Title
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    \[x\geq -1\] as before

    • 2 years ago
  7. miababygirl1987 Group Title
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    5( x + 1) - 3( x - 1) > -9

    • 2 years ago
  8. satellite73 Group Title
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    \[x\geq -\frac{17}{2}\]

    • 2 years ago
  9. viniterranova Group Title
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    -3x+12-2x-8=<-9; -5x+4=<-9; -5x=<-4-9; -5x=<-13; (x-1) x>=13/5

    • 2 years ago
  10. miababygirl1987 Group Title
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    4(x + 3) > 6(x - 5)

    • 2 years ago
  11. viniterranova Group Title
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    4x+12>6x-30; 4x-6x>-30-12; -2x>-42 (x-1) x<42/2; x<21

    • 2 years ago
  12. Chlorophyll Group Title
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    x -1 >= -2 ->x >= -1

    • 2 years ago
  13. miababygirl1987 Group Title
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    3x + 5 < 5

    • 2 years ago
  14. Wolf77 Group Title
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    In general you want to approach inequalities the same way that you would a simple equality however when you multiply or divide by a negative then you must change the direction of the inequality. i.e.) -x > 5 becomes x < 5.

    • 2 years ago
  15. miababygirl1987 Group Title
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    ok for 3x+ 5< 5 I got x ≥ -3 is that right ?

    • 2 years ago
  16. miababygirl1987 Group Title
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    sorry -5(x + 3) ≥ 0 I got x ≥ -3

    • 2 years ago
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