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anonymous
 4 years ago
Anyone Know how to do this kind of work that will help me through these problems would be really helpful!!!!!!!! 7( x  1 ) ≥ 14
anonymous
 4 years ago
Anyone Know how to do this kind of work that will help me through these problems would be really helpful!!!!!!!! 7( x  1 ) ≥ 14

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anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0divide by 7 get \[x1\geq 2\] then add 1 to both sides to get \[x\geq 1\]

saifoo.khan
 4 years ago
Best ResponseYou've already chosen the best response.0\[x1 \ge  \frac{14}{7}\] \[x1 \ge  2\] Add 1 on both sides, \[x \ge 2 +1\] \[x \ge Answer\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.03( x  4 )  2( x + 4) ≤ 9

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.07x7>=14; 7x>=14+7; x>=7/7; x>=1

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.03( x  4 )  2( x + 4) ≤ 9

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0\[x\geq 1\] as before

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.05( x + 1)  3( x  1) > 9

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0\[x\geq \frac{17}{2}\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.03x+122x8=<9; 5x+4=<9; 5x=<49; 5x=<13; (x1) x>=13/5

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.04x+12>6x30; 4x6x>3012; 2x>42 (x1) x<42/2; x<21

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0In general you want to approach inequalities the same way that you would a simple equality however when you multiply or divide by a negative then you must change the direction of the inequality. i.e.) x > 5 becomes x < 5.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0ok for 3x+ 5< 5 I got x ≥ 3 is that right ?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0sorry 5(x + 3) ≥ 0 I got x ≥ 3
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