krypton
since e^0=1
what is e^1=



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dumbcow
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just e^1 or 2.72

krypton
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actual am solving a calculus problem) of derivative

krypton
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solving for y,inother to get the equation of a tangent line

krypton
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y=x^3 e^x when x=1

krypton
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if i substitute the 1 into x my answer comes out as "e"

dumbcow
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ok
so y' wil give you the slope
y' = 3x^2*e^x + x^3*e^x
x=1
y'(1) = 3e +e = 4e

krypton
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ok thanks

krypton
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just wanted to be sure if i were doing the right thing

dumbcow
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no problem :)