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purplemouse
 3 years ago
so I need help with the steps to simplify this: csc(arctan x)
I know that sqrt(x^2 +1) = sec t
and x = tan t; t= arctan(x)
purplemouse
 3 years ago
so I need help with the steps to simplify this: csc(arctan x) I know that sqrt(x^2 +1) = sec t and x = tan t; t= arctan(x)

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satellite73
 3 years ago
Best ResponseYou've already chosen the best response.1dw:1329631016942:dw

satellite73
 3 years ago
Best ResponseYou've already chosen the best response.1sorry for the lousy picture, but cosecant is "hypotenuse over opposite" at least that is the simpleminded way of thinking about it

satellite73
 3 years ago
Best ResponseYou've already chosen the best response.1you get \[\frac{\sqrt{1x^2}}{x}\] in one step after solving for the hypotenuse

purplemouse
 3 years ago
Best ResponseYou've already chosen the best response.0ah, it was the picture I was having trouble with. Thanks!
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