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anonymous
 4 years ago
so I need help with the steps to simplify this: csc(arctan x)
I know that sqrt(x^2 +1) = sec t
and x = tan t; t= arctan(x)
anonymous
 4 years ago
so I need help with the steps to simplify this: csc(arctan x) I know that sqrt(x^2 +1) = sec t and x = tan t; t= arctan(x)

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anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0dw:1329631016942:dw

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0sorry for the lousy picture, but cosecant is "hypotenuse over opposite" at least that is the simpleminded way of thinking about it

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0you get \[\frac{\sqrt{1x^2}}{x}\] in one step after solving for the hypotenuse

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0ah, it was the picture I was having trouble with. Thanks!
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