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purplemouse

  • 4 years ago

so I need help with the steps to simplify this: csc(arctan x) I know that sqrt(x^2 +1) = sec t and x = tan t; t= arctan(x)

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  1. anonymous
    • 4 years ago
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    |dw:1329631016942:dw|

  2. anonymous
    • 4 years ago
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    sorry for the lousy picture, but cosecant is "hypotenuse over opposite" at least that is the simpleminded way of thinking about it

  3. anonymous
    • 4 years ago
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    you get \[\frac{\sqrt{1-x^2}}{x}\] in one step after solving for the hypotenuse

  4. purplemouse
    • 4 years ago
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    ah, it was the picture I was having trouble with. Thanks!

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