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so I need help with the steps to simplify this: csc(arctan x)
I know that sqrt(x^2 +1) = sec t
and x = tan t; t= arctan(x)
 2 years ago
 2 years ago
so I need help with the steps to simplify this: csc(arctan x) I know that sqrt(x^2 +1) = sec t and x = tan t; t= arctan(x)
 2 years ago
 2 years ago

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satellite73Best ResponseYou've already chosen the best response.1
dw:1329631016942:dw
 2 years ago

satellite73Best ResponseYou've already chosen the best response.1
sorry for the lousy picture, but cosecant is "hypotenuse over opposite" at least that is the simpleminded way of thinking about it
 2 years ago

satellite73Best ResponseYou've already chosen the best response.1
you get \[\frac{\sqrt{1x^2}}{x}\] in one step after solving for the hypotenuse
 2 years ago

purplemouseBest ResponseYou've already chosen the best response.0
ah, it was the picture I was having trouble with. Thanks!
 2 years ago
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