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purplemouse
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simplify: tan^3(arcsec (x/2))
x= 2sec t
sqrt(x^2 4) = 2 tan t
t = arcsec (x/2)
 2 years ago
 2 years ago
purplemouse Group Title
simplify: tan^3(arcsec (x/2)) x= 2sec t sqrt(x^2 4) = 2 tan t t = arcsec (x/2)
 2 years ago
 2 years ago

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satellite73 Group TitleBest ResponseYou've already chosen the best response.2
dw:1329633693726:dw
 2 years ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.2
it is all in the triangle
 2 years ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.2
there is a picture where the arc secant is x/2
 2 years ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.2
find remaining side by pythagoras, get \[\sqrt{x^24}\]
 2 years ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.2
then find the tangent, then cube the result
 2 years ago

dumbcow Group TitleBest ResponseYou've already chosen the best response.0
you could also do a straight substitution tan = sqrt(sec^2 1) tan = sqrt(x^2/4 1) tan = sqrt(x^2 4)/2 tan^3 = (x^24)sqrt(x^24) / 8
 2 years ago

purplemouse Group TitleBest ResponseYou've already chosen the best response.0
so I have (x^2 4)\[\sqrt{(x ^{2}}4)\]
 2 years ago

purplemouse Group TitleBest ResponseYou've already chosen the best response.0
I get it now
 2 years ago
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