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Trigonometry question on R cos (theta  alpha). http://d.pr/L96v
 2 years ago
 2 years ago
Trigonometry question on R cos (theta  alpha). http://d.pr/L96v
 2 years ago
 2 years ago

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adnanchowdhuryBest ResponseYou've already chosen the best response.0
Second part of the question is what i need help with. My answer to the first part: \[\sqrt{17} \cos (\Theta + \alpha)\] Second part: My answers are: 46.9 and 46.9. But answers says: 46.9 and 75?
 2 years ago

adnanchowdhuryBest ResponseYou've already chosen the best response.0
Edit: I mean to write, the answer to my first answer was √cos(Θ+14)
 2 years ago

satellite73Best ResponseYou've already chosen the best response.0
[r\sin(x+\theta)\] where \[r=\sqrt{a^2+b^2}, \tan(\theta)=\frac{a}{b}\]if i recall correctly
 2 years ago

satellite73Best ResponseYou've already chosen the best response.0
oops you want cosine, sorry
 2 years ago

satellite73Best ResponseYou've already chosen the best response.0
same idea but this time \[r\cos(x  \theta)\] same r but \[\tan(\theta)=\frac{b}{a}\]
 2 years ago

satellite73Best ResponseYou've already chosen the best response.0
so we need \[\theta\] in degrees i take it, yes?
 2 years ago

satellite73Best ResponseYou've already chosen the best response.0
i get \[\theta = 14.4\] giving \[\sqrt{17}\cos(x+14.4)\]
 2 years ago

satellite73Best ResponseYou've already chosen the best response.0
\[\sqrt{17}\cos(x+14.4)=2\] \[\cos(x+14.4)=\frac{2}{\sqrt{17}}\] \[x=\cos^{1}(\frac{2}{\sqrt{17}})14.4\]
 2 years ago

adnanchowdhuryBest ResponseYou've already chosen the best response.0
between 180 and 180 degrees.
 2 years ago

adnanchowdhuryBest ResponseYou've already chosen the best response.0
Mark scheme: http://d.pr/ubFq Where does the value 75 come from?
 2 years ago
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