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anonymous
 4 years ago
a quadrilateral ABCD,<B=130,<c=60,angle bisectors of<Aand<D meet at P.FIND<APD.
anonymous
 4 years ago
a quadrilateral ABCD,<B=130,<c=60,angle bisectors of<Aand<D meet at P.FIND<APD.

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anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0dw:1329669343302:dw

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0????????????????????????????????????????????????????????????????????????

2bornot2b
 4 years ago
Best ResponseYou've already chosen the best response.1dw:1329670418181:dw We get two equations from the figure \[x+y+p=180(1)\]\[x+y+(360p)+130+60=540\implies x+yp=10(2)\]

2bornot2b
 4 years ago
Best ResponseYou've already chosen the best response.1\[2p=\frac{190}{2}[(1)(2)]\]\[p=95\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0we will plz mark the angles which i hav given in ma figure

2bornot2b
 4 years ago
Best ResponseYou've already chosen the best response.1dw:1329670804174:dw \[\huge labelled\]

2bornot2b
 4 years ago
Best ResponseYou've already chosen the best response.1I subtracted the two equations. Note, first I created two equations, and then I subtracted the second from the first.

2bornot2b
 4 years ago
Best ResponseYou've already chosen the best response.1dw:1329671057692:dw

2bornot2b
 4 years ago
Best ResponseYou've already chosen the best response.1Did you understand that?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0ya thnkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkk

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0another question is coming

2bornot2b
 4 years ago
Best ResponseYou've already chosen the best response.1OK, just post it as a new question.
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