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parvathy

a quadrilateral ABCD,<B=130,<c=60,angle bisectors of<Aand<D meet at P.FIND<APD.

  • 2 years ago
  • 2 years ago

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  1. parvathy
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    |dw:1329669343302:dw|

    • 2 years ago
  2. parvathy
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    answer is 95

    • 2 years ago
  3. parvathy
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    wht r u doing?

    • 2 years ago
  4. parvathy
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    answer is 95

    • 2 years ago
  5. parvathy
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    but answer is 95 knw

    • 2 years ago
  6. parvathy
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    ????????????????????????????????????????????????????????????????????????

    • 2 years ago
  7. parvathy
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    k

    • 2 years ago
  8. parvathy
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    k

    • 2 years ago
  9. 2bornot2b
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    |dw:1329670418181:dw| We get two equations from the figure \[x+y+p=180--------(1)\]\[x+y+(360-p)+130+60=540\implies x+y-p=-10-------(2)\]

    • 2 years ago
  10. 2bornot2b
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    \[2p=\frac{190}{2}------------[(1)-(2)]\]\[p=95\]

    • 2 years ago
  11. parvathy
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    we will plz mark the angles which i hav given in ma figure

    • 2 years ago
  12. 2bornot2b
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    |dw:1329670804174:dw| \[\huge labelled\]

    • 2 years ago
  13. parvathy
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    how u got 2p

    • 2 years ago
  14. parvathy
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    190?

    • 2 years ago
  15. parvathy
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    got

    • 2 years ago
  16. 2bornot2b
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    I subtracted the two equations. Note, first I created two equations, and then I subtracted the second from the first.

    • 2 years ago
  17. parvathy
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    2P?

    • 2 years ago
  18. parvathy
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    K

    • 2 years ago
  19. parvathy
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    U R VERY BRILLIANT

    • 2 years ago
  20. 2bornot2b
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    |dw:1329671057692:dw|

    • 2 years ago
  21. parvathy
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    k brilliant boy

    • 2 years ago
  22. 2bornot2b
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    Did you understand that?

    • 2 years ago
  23. parvathy
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    ya thnkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkk

    • 2 years ago
  24. parvathy
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    another question is coming

    • 2 years ago
  25. 2bornot2b
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    OK, just post it as a new question.

    • 2 years ago
  26. parvathy
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    k

    • 2 years ago
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