parvathy
a quadrilateral ABCD,<B=130,<c=60,angle bisectors of<Aand<D meet at P.FIND<APD.



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parvathy
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dw:1329669343302:dw

parvathy
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answer is 95

parvathy
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wht r u doing?

parvathy
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answer is 95

parvathy
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but answer is 95 knw

parvathy
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????????????????????????????????????????????????????????????????????????

parvathy
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k

parvathy
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k

2bornot2b
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dw:1329670418181:dw
We get two equations from the figure
\[x+y+p=180(1)\]\[x+y+(360p)+130+60=540\implies x+yp=10(2)\]

2bornot2b
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\[2p=\frac{190}{2}[(1)(2)]\]\[p=95\]

parvathy
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we will plz mark the angles which i hav given in ma figure

2bornot2b
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dw:1329670804174:dw
\[\huge labelled\]

parvathy
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how u got 2p

parvathy
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190?

parvathy
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got

2bornot2b
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I subtracted the two equations.
Note, first I created two equations, and then I subtracted the second from the first.

parvathy
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2P?

parvathy
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K

parvathy
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U R VERY BRILLIANT

2bornot2b
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dw:1329671057692:dw

parvathy
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k
brilliant boy

2bornot2b
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Did you understand that?

parvathy
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ya thnkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkk

parvathy
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another question is coming

2bornot2b
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OK, just post it as a new question.

parvathy
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k