Got Homework?
Connect with other students for help. It's a free community.
Here's the question you clicked on:
← 55 members online
 0 viewing

This Question is Closed

TuringTestBest ResponseYou've already chosen the best response.1
hah, you got that from that sqrt(x2)/sqrt(x1) thing, right?
 2 years ago

TuringTestBest ResponseYou've already chosen the best response.1
sect(tan^2t)=sect(sec^2t1)=sec^3tsect
 2 years ago

TuringTestBest ResponseYou've already chosen the best response.1
\[\int\sec^3 tdt\]\[u=\sec t\]\[dv=\sec^2 t\]integrate by parts
 2 years ago

purplemouseBest ResponseYou've already chosen the best response.1
I've gotten that far in the equation already, just not sure what to do with the sec^3 t
 2 years ago

TuringTestBest ResponseYou've already chosen the best response.1
^there it is this will be one of those integrals that repeats, so you will wind up adding the integral of sec^3 to both sides you will still have to integrate sec though, hope you remember how to do that ;)
 2 years ago
See more questions >>>
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.