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Just add the components of all of the vectors to find the resultant displacement. First he moves 2.6 km north, then he moves 4 km east then he moves 3.1 km north east.
Okay Nath what is it about this problem that is confusing to you?

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Other answers:

The first displacement he moves 2.6 km but he has no horizontal displacement. The second displacement he moves 4 km which is all horizontal. The third displacement he moves 3.1 km which is only part horizontal (You should be able to figure out the horizontal component from the last post)
x=5.7 cos(45) i added the 2.6 to 3.1
Not quite. For the x component 2.6 wouldn't be a part of it because none of it is in the x direction
you mean that 3.1 is not completely horiziontal
Yes. Also, the component that is 2.6 km is all in the y direction so none of it will be on the x component
so what do i have to do
How far did the truck travel along the x axis?
What about the 3.1 km he traveled north east? Part of that displacement is along the x axis.
i know to find the x component it would be 3.1 cos(45)
That's correct :) and that plus the 4 km is how far he moved along the x axis
so i could add the 2.6 to the 3.1 because the 2.6 is completely horizontal while the 3.1 is partially horizontal. however i have to take it into account
i mean i couldnt*
The 2.6 is completely vertical. The 4.0 is completely horizontal
So add up the horizontal parts :)
I'm about to have to head out :/ sorry I couldn't help you finish the problem. Just add up all the x components of all the vectors and all the y components of the vectors and this will create a new vector with the x component you just calculated and the y component you just calculated.
okay thank u so much

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