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Just add the components of all of the vectors to find the resultant displacement. First he moves 2.6 km north, then he moves 4 km east then he moves 3.1 km north east.
Okay Nath what is it about this problem that is confusing to you?
The first displacement he moves 2.6 km but he has no horizontal displacement. The second displacement he moves 4 km which is all horizontal. The third displacement he moves 3.1 km which is only part horizontal (You should be able to figure out the horizontal component from the last post)
x=5.7 cos(45) i added the 2.6 to 3.1
Not quite. For the x component 2.6 wouldn't be a part of it because none of it is in the x direction
you mean that 3.1 is not completely horiziontal
Yes. Also, the component that is 2.6 km is all in the y direction so none of it will be on the x component
so what do i have to do
How far did the truck travel along the x axis?
What about the 3.1 km he traveled north east? Part of that displacement is along the x axis.
i know to find the x component it would be 3.1 cos(45)
That's correct :) and that plus the 4 km is how far he moved along the x axis
so i could add the 2.6 to the 3.1 because the 2.6 is completely horizontal while the 3.1 is partially horizontal. however i have to take it into account
i mean i couldnt*
The 2.6 is completely vertical. The 4.0 is completely horizontal
So add up the horizontal parts :)
I'm about to have to head out :/ sorry I couldn't help you finish the problem. Just add up all the x components of all the vectors and all the y components of the vectors and this will create a new vector with the x component you just calculated and the y component you just calculated.
okay thank u so much