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Could someone help me with finding the ratios for sin x and cos x in a right triangle where the hypotenuse is 12, the opposite is 5, and the adjacent is the square root of 119 (10.9 if I round/simplify it, but...)?
 2 years ago
 2 years ago
Could someone help me with finding the ratios for sin x and cos x in a right triangle where the hypotenuse is 12, the opposite is 5, and the adjacent is the square root of 119 (10.9 if I round/simplify it, but...)?
 2 years ago
 2 years ago

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chemwileBest ResponseYou've already chosen the best response.1
sinx = opposite/hypotenus = 5/12 cosx = adjacent/hypotenuse = sqrt(119)/12
 2 years ago
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