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anonymous
 4 years ago
Could someone help me with finding the ratios for sin x and cos x in a right triangle where the hypotenuse is 12, the opposite is 5, and the adjacent is the square root of 119 (10.9 if I round/simplify it, but...)?
anonymous
 4 years ago
Could someone help me with finding the ratios for sin x and cos x in a right triangle where the hypotenuse is 12, the opposite is 5, and the adjacent is the square root of 119 (10.9 if I round/simplify it, but...)?

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anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0sinx = opposite/hypotenus = 5/12 cosx = adjacent/hypotenuse = sqrt(119)/12
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