## keketsu Group Title Simplify: /[2x(2x)^(x-1) + (ln (2x))(2x)^x/] I'm particularly interested in how to work with /[(2x)^(x-1)/]. thanks. 2 years ago 2 years ago

1. vengeance921 Group Title

$2x(2x)^{x-1}+(Ln(2x))(2x)^{x}$ Is this the question?

2. amistre64 Group Title

$a^{(b+c)}=a^b * a^c$

3. vengeance921 Group Title

They have a natural logarithm there, right?

4. amistre64 Group Title

yes, but it looks to just care about factoring out the 2x

5. keketsu Group Title

Yes, vengeance, sorry about the extra brackets. And yes, amistre64, you gave me the rule I was looking for. Thanks guys. How do I mark these equations so that the system recognizes them as math problems, btw?

6. amistre64 Group Title

$(2x)^1*(2x)^{(x-1)}=(2x)^{(x-1+1)}$

7. amistre64 Group Title

latex i assume

8. vengeance921 Group Title

@Keketsu=Can you just post the real question please? Lol

9. SchoolSlacker Group Title

2x(2x)^{x-1} sorry for asking my own question in your question but i just wanted to know with this would you do the factorisation with the outer number first or the indices with the brackets?

10. amistre64 Group Title

a demonstration to type in latex would be futile since the system would parse it as latex and not a demonstration :)

11. keketsu Group Title

@Vengeance921, what you posted is the equation, but it is dealing with the (2x)^(x-1) that I was having trouble with. So that's (2x^x) * (2x^-1) or (2x^x)/2x?

12. amistre64 Group Title

School, there is no real rule for procedure; only that it makes mathical sense in the end :)

13. amistre64 Group Title

$\frac{2x*2x^x}{2x}$is one way to present it, yes

14. SchoolSlacker Group Title

Thanks i just saw it in the equation, and i had no idea :P

15. keketsu Group Title

Wonderful. Thanks for the help.

16. amistre64 Group Title

youre welcome