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\[2x(2x)^{x-1}+(Ln(2x))(2x)^{x}\]
Is this the question?

\[a^{(b+c)}=a^b * a^c\]

They have a natural logarithm there, right?

yes, but it looks to just care about factoring out the 2x

\[(2x)^1*(2x)^{(x-1)}=(2x)^{(x-1+1)}\]

latex i assume

School, there is no real rule for procedure; only that it makes mathical sense in the end :)

\[\frac{2x*2x^x}{2x}\]is one way to present it, yes

Thanks i just saw it in the equation, and i had no idea :P

Wonderful. Thanks for the help.

youre welcome