anonymous
  • anonymous
In triangle PQR, < PQR is right and QT is an altitude Name the three similar triangles. How do you name them?! O.o idk but I got : triangle PQT is similar to triangle PRQ triangle TQR is similar to triangle QPR triangle PQT is similar to triangle QPT ?
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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Mertsj
  • Mertsj
Need a posting that we can understand.
anonymous
  • anonymous
Do you want me to draw it ?
Mertsj
  • Mertsj
yep

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anonymous
  • anonymous
Okay, I'll try.
anonymous
  • anonymous
|dw:1329752026742:dw|
Directrix
  • Directrix
Should be a right angle at T ??
Mertsj
  • Mertsj
Separate the triangles and draw them all in similar position.
anonymous
  • anonymous
yes @ directrix
anonymous
  • anonymous
|dw:1329752295176:dw|
Directrix
  • Directrix
If an altitude is drawn to the hypotenuse of a right triangle, the two triangles formed are similar to each other and to the given right triangle.
Directrix
  • Directrix
Triangle PQR ~ Triangle QTR ~ Triangle PTQ
anonymous
  • anonymous
So, is this correct? triangle PQT is similar to triangle PRQ triangle TQR is similar to triangle QPR triangle PQT is similar to triangle QPT
Mertsj
  • Mertsj
|dw:1329752679773:dw|
Mertsj
  • Mertsj
Directrix is correct.
Directrix
  • Directrix
Match up right angles of all 3. Of the larger and one smaller, then match up angles they share. The 3rd pair of vertices have no place to go but to each other.
Directrix
  • Directrix
@ Mert --> Right angle at T on drawing or the theorem is not valid.
anonymous
  • anonymous
Wait, can you just PLEASE tell me if what I did is correct or wrong ?
anonymous
  • anonymous
I think
Directrix
  • Directrix
@Fool --> Valid for all right triangles satisfying the hypothesis of the theorem I wrote somewhere up this thread.
Directrix
  • Directrix
triangle PQT is similar to triangle QPT --> This third section of Help's answer seems to name the same two triangles. Look at that again, Help.
phi
  • phi
@need triangle PQT is similar to triangle QPT . this is the same triangle. The 3 are PQR, QTR, PTQ (note that you should order the vertices to show what angles (sides) are congruent)
anonymous
  • anonymous
I know, I need them to be separate.. like what I did..
phi
  • phi
*similar (not congruent!)
anonymous
  • anonymous
So, apparently, \( \angle TQR = \angle TPQ \) hence the correspondence
phi
  • phi
there are only 3 angles: 90, A, and (90-A), so it is easy to show similarity of triangles
phi
  • phi
Name the three similar triangles. means write down triangle PQR, triangle QTR, triangle PTQ
anonymous
  • anonymous
Yeah, kinda.. I understand how you name the big triangle with one of the small triangles but what is I dont get or don't how is how to name the small triangle with the other small triangle? & this is => triangle PQT is similar to triangle QPT wrong?
Directrix
  • Directrix
Be systematic. It's easy to get confused on these. Start with the original triangle. Call it what you like. You called it PRQ, I think. State the similarity of PRQ to one of the smaller triangles, say PQT. First, match the right angles from larger triangle to smaller. Q has to match to T. They share angle P so P has to match to P. That forces R of the larger triangle to Q of the smaller. Result : Triangle PRQ ~ Triangle PQT Next, match Triangle PRQ to the other triangle keeping the same order of letters, PRQ. Then, the two smaller triangle will be similar to each other by the transitive property.
anonymous
  • anonymous
Aooh! So, what I did is correct?! :D
phi
  • phi
you name a triangle by listing its vertices.
anonymous
  • anonymous
really? -.- what is triangle PQT similar to?
phi
  • phi
what is triangle PQT similar to? triangle PRQ and triangle QTR
anonymous
  • anonymous
Why not PRQ with QRT ?
anonymous
  • anonymous
or same thing?
phi
  • phi
triangle QTR is the same as QRT. (same points). But if I did it write, when we ask what is triangle PQT similar to, the P corresponds to Q, the Q to T, and the T to R
phi
  • phi
*write -> right i.e. correctly
Directrix
  • Directrix
I was trying to teach you how to do this but so many people have posted so much stuff that I have lost track. This is the way I do these problems: Be systematic. It's easy to get confused on these. Start with the original triangle. Call it what you like. You called it PRQ, I think. State the similarity of PRQ to one of the smaller triangles, say PQT. First, match the right angles from larger triangle to smaller. Q has to match to T. They share angle P so P has to match to P. That forces R of the larger triangle to Q of the smaller. Result : Triangle PRQ ~ Triangle PQT Next, match Triangle PRQ to the other triangle keeping the same order of letters, PRQ. Then, the two smaller triangle will be similar to each other by the transitive property. That does not mean what you did is incorrect. As best I remember, yours were correct except for the third pair of triangles in which you listed the same triangle twice.
anonymous
  • anonymous
Man! This is confusing -.- but I think I get it now.. thanks to you guys!! =D I saw where I went wrong in the last one. Thank you =))
phi
  • phi
Labeling the angles helps. but you are right, it can get confusing
anonymous
  • anonymous
Oh yeah!! i remembered something just don't know if it's right or wrong..
anonymous
  • anonymous
|dw:1329758666185:dw|
phi
  • phi
|dw:1329758695491:dw|
anonymous
  • anonymous
sorry, the computer just froze! I was saying that these two angles are always congruent?

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