AcidRa1n
See 18 and 20 Pic



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AcidRa1n
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anonymous
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take the square root fo the ratios

anonymous
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first one for example
\[\frac{4}{16}=\frac{1}{4}\] so ratio of the perimeter is
\[\frac{\sqrt{1}}{\sqrt{4}}=\frac{1}{2}\]


AcidRa1n
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How did you get 4/16?!?!

anonymous
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it said ratio was 4 to 16 in the first one

AcidRa1n
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Oh i thought it was 18 can you do 18?

anonymous
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so i just made it in to a fraction

anonymous
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yes
\[\frac{75}{12}\] reduces conveniently to
\[\frac{25}{4}\] now you can easily take the square root and get
\[\frac{5}{2}\]

AcidRa1n
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ahh thanks

anonymous
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similarly
\[\frac{49}{9}\] take the square root directly get
\[\frac{7}{3}\] etc
got it?

AcidRa1n
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yeah! Thanks!

anonymous
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yw

AcidRa1n
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medal for me? :D