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s(t)=-4.9t+vt+s A projectile is shot upward from the surface of Earth with an initial velocity of 120 meters per sec. What is its velocity ater 5 seconds? After 10 seconds?

Mathematics
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\[s(t)=-4.9t+v _{0}t+s _{0}\]
derivative should give velocity
v(t) = -9.8t + 120

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Other answers:

solve for t=5 and t = 10
how did you get that derivative?
ok i get 4.9(2)t is the derivative of 4.9t^6
but why wouldnt 120 become 0 since it is a constant?
oh wait it would be 120t wouldnt it?

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