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anonymous
 4 years ago
s(t)=4.9+vt+s
To estimate the height of a building, a stone is dropped from the top of the building into a pool of water at ground level. How high is the building if the splash is seen 5.6 seconds after the stone is dropped?
anonymous
 4 years ago
s(t)=4.9+vt+s To estimate the height of a building, a stone is dropped from the top of the building into a pool of water at ground level. How high is the building if the splash is seen 5.6 seconds after the stone is dropped?

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anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0hmm are you aloud to use derivatives?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.04.9t^2 I think you mean :)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0and yes i can use derivatives

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0im just not sure how to use the information given

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0im so confused right now

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0this rate of change thing is going to do me in

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0hmm so vo and so are both unknown?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0yes but i am assuming s0 would = 0 at 5.6 seconds

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0yeah thats right the vo is just the pain in the a part of the problem

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0wait wait wait, it seems to be lacking the classic physics wording of it was dropped with an unknown intial velocity, it being dropped and not thrown I would maybe go as far to say the the intial velocity is 0

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0that seems like it might be too easy though

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0we dont drop things with an intial velocity though lol, thats against the definition of dropping lol

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0I am so lost on any problems dealing with rate of change

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0I may have to drop this course if I do not pick these up soon :(

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.04.9(5.6^2) should be your answer assuming that dropping means letting go from rest

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0I am having a hard time telling where the information they give me plugs in

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Say they give me a distance of 108 meters, I assume thats s

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0if they give me a velocity that v0t

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0and a measurement of time = t

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0so if they give me t and vot

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0i find the derivative

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0and solve for the value of t

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0but when they give me t and s im lost lol

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0s(t)= 4.9t^2+v0t+108?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0and when they only give me t i am more than lost

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0no that more like my next problem, but if i were given that question

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Here ill read type you a problem from my book and try to help clarify things

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0i do not know what to do

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Hokay so, A person standing at the edge of a cliff throws a rock directly upward. it is observed that 2 seconds later the rock is at its maximum height and that 5 seconds after that, it hits the ground at the base of the cliff?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0i have no idea how to solve that

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0But they are questions like that correct?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0I'll show you how to appoarch it if it is

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0(this is straight from my change of rate section)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0hmmmm on my original question

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0s(t)=4.9+vt+s v(t)=s'(t)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0so 9.8t+v would be the derivative

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.09.8(5.6)+v=0 v= 54.88

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0would that be the velocity?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0thats your impact velocity

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0ok so when s=0 Velocity = 54.88?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0assuming that v0=0 yes

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0now i confused myself lol

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0hahaha remember the derivative of the distance equation is the velocity at time equation

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0at 5.6 secs s=0 since thats impact right?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0wait nno no s0 is not o

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0here label the equation like this it makes it more clear. So 4.9t^2+v0t+s0= s

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0so at time t=5.6s s would be 0 not s0

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0other wise you would get a negative height, it really doesnt matter which way you do it but you should do it right when you are first doing it.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0well i am trying to understand

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0I'm sorry I really havent been too much help but that question is horribly worded. If I were in your shoes I would assume that the initial velocity is 0 as progress from there. As long as you understand the relationships between the equations, it will make solving these very simple. Drawing whats going on helps

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.04.9t^2+vt+s 9.8t+v is the derivative correct?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0with that i can get the velocity at impact

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.09.8(5.6)+v=0 v= 54.88

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0yes but you need to know what v initial is

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0well wouldnt that be as simple as making t 0?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0I dont think you can do that because you are stating that v(5.6)=0

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Try reposting this in the physics section, they are really good at explain this kind of stuff

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0the initial velocity is 0

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Sorry I was trying to be ambiguous I didnt want to give you improper information

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0I am in your same level class lol

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0I just do about 6 hours of hw a day

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0i took too many courses

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0yeah it blows I have no social life atm just study study

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0com 101 is more time consuming than i thought

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0:( yeah thats the draw back of underestimating courses. I'm taking physics, chem, physics lab, calc and I really thought this semester would be a tad less stressful

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0chem, com 101, calc and us history

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0history and chem is ok, but com 101 is taking way to much of my time

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0us history=gun to my head i finished all of my gen ed first so I could figure out what I wanna do

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0taking way to much time writing and preparing for speeches

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Thats why I stick to courses that strictly deal with numbers

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0lol its a req for my degree or i would never touch it

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0:( I just wanna take comparitive virology already, all of these courses building up to it are just BS
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