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ChrisV

  • 4 years ago

s(t)=-4.9+vt+s To estimate the height of a building, a stone is dropped from the top of the building into a pool of water at ground level. How high is the building if the splash is seen 5.6 seconds after the stone is dropped?

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  1. ChrisV
    • 4 years ago
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    s(t)=-4.9t+vt+s

  2. Awstinf
    • 4 years ago
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    hmm are you aloud to use derivatives?

  3. ChrisV
    • 4 years ago
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    missed a t >.<

  4. Awstinf
    • 4 years ago
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    -4.9t^2 I think you mean :)

  5. ChrisV
    • 4 years ago
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    yea

  6. ChrisV
    • 4 years ago
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    -4.9t^2 +vt+s

  7. ChrisV
    • 4 years ago
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    and yes i can use derivatives

  8. ChrisV
    • 4 years ago
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    im just not sure how to use the information given

  9. ChrisV
    • 4 years ago
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    im so confused right now

  10. ChrisV
    • 4 years ago
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    this rate of change thing is going to do me in

  11. Awstinf
    • 4 years ago
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    hmm so vo and so are both unknown?

  12. ChrisV
    • 4 years ago
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    yes but i am assuming s0 would = 0 at 5.6 seconds

  13. ChrisV
    • 4 years ago
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    since thats impact

  14. Awstinf
    • 4 years ago
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    yeah thats right the vo is just the pain in the a part of the problem

  15. Awstinf
    • 4 years ago
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    wait wait wait, it seems to be lacking the classic physics wording of it was dropped with an unknown intial velocity, it being dropped and not thrown I would maybe go as far to say the the intial velocity is 0

  16. Awstinf
    • 4 years ago
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    that seems like it might be too easy though

  17. Awstinf
    • 4 years ago
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    we dont drop things with an intial velocity though lol, thats against the definition of dropping lol

  18. ChrisV
    • 4 years ago
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    I am so lost on any problems dealing with rate of change

  19. ChrisV
    • 4 years ago
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    I may have to drop this course if I do not pick these up soon :(

  20. Awstinf
    • 4 years ago
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    :(

  21. Awstinf
    • 4 years ago
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    4.9(5.6^2) should be your answer assuming that dropping means letting go from rest

  22. ChrisV
    • 4 years ago
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    I am having a hard time telling where the information they give me plugs in

  23. ChrisV
    • 4 years ago
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    Say they give me a distance of 108 meters, I assume thats s

  24. ChrisV
    • 4 years ago
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    if they give me a velocity that v0t

  25. ChrisV
    • 4 years ago
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    and a measurement of time = t

  26. ChrisV
    • 4 years ago
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    so if they give me t and vot

  27. ChrisV
    • 4 years ago
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    i find the derivative

  28. ChrisV
    • 4 years ago
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    and solve for the value of t

  29. ChrisV
    • 4 years ago
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    but when they give me t and s im lost lol

  30. Awstinf
    • 4 years ago
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    s(t)= -4.9t^2+v0t+108?

  31. ChrisV
    • 4 years ago
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    and when they only give me t i am more than lost

  32. ChrisV
    • 4 years ago
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    no that more like my next problem, but if i were given that question

  33. Awstinf
    • 4 years ago
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    Here ill read type you a problem from my book and try to help clarify things

  34. ChrisV
    • 4 years ago
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    i do not know what to do

  35. Awstinf
    • 4 years ago
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    read-type*

  36. Awstinf
    • 4 years ago
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    Hokay so, A person standing at the edge of a cliff throws a rock directly upward. it is observed that 2 seconds later the rock is at its maximum height and that 5 seconds after that, it hits the ground at the base of the cliff?

  37. Awstinf
    • 4 years ago
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    questions like that?

  38. ChrisV
    • 4 years ago
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    i have no idea how to solve that

  39. Awstinf
    • 4 years ago
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    But they are questions like that correct?

  40. Awstinf
    • 4 years ago
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    I'll show you how to appoarch it if it is

  41. Awstinf
    • 4 years ago
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    (this is straight from my change of rate section)

  42. ChrisV
    • 4 years ago
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    hmmmm on my original question

  43. Awstinf
    • 4 years ago
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    yeah?

  44. ChrisV
    • 4 years ago
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    s(t)=-4.9+vt+s v(t)=s'(t)

  45. ChrisV
    • 4 years ago
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    oops 4.9t^2

  46. ChrisV
    • 4 years ago
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    so -9.8t+v would be the derivative

  47. Awstinf
    • 4 years ago
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    yeah

  48. ChrisV
    • 4 years ago
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    -9.8(5.6)+v=0 v= 54.88

  49. ChrisV
    • 4 years ago
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    would that be the velocity?

  50. Awstinf
    • 4 years ago
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    thats your impact velocity

  51. ChrisV
    • 4 years ago
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    ok so when s=0 Velocity = 54.88?

  52. Awstinf
    • 4 years ago
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    assuming that v0=0 yes

  53. ChrisV
    • 4 years ago
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    now i confused myself lol

  54. Awstinf
    • 4 years ago
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    hahaha remember the derivative of the distance equation is the velocity at time equation

  55. ChrisV
    • 4 years ago
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    -4.9t^2 +vt+s

  56. ChrisV
    • 4 years ago
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    well if s=distance

  57. ChrisV
    • 4 years ago
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    at 5.6 secs s=0 since thats impact right?

  58. Awstinf
    • 4 years ago
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    yes

  59. Awstinf
    • 4 years ago
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    wait nno no s0 is not o

  60. Awstinf
    • 4 years ago
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    0*

  61. Awstinf
    • 4 years ago
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    here label the equation like this it makes it more clear. So 4.9t^2+v0t+s0= s

  62. Awstinf
    • 4 years ago
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    so at time t=5.6s s would be 0 not s0

  63. Awstinf
    • 4 years ago
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    other wise you would get a negative height, it really doesnt matter which way you do it but you should do it right when you are first doing it.

  64. ChrisV
    • 4 years ago
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    hehe

  65. ChrisV
    • 4 years ago
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    well i am trying to understand

  66. Awstinf
    • 4 years ago
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    I'm sorry I really havent been too much help but that question is horribly worded. If I were in your shoes I would assume that the initial velocity is 0 as progress from there. As long as you understand the relationships between the equations, it will make solving these very simple. Drawing whats going on helps

  67. ChrisV
    • 4 years ago
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    -4.9t^2+vt+s 9.8t+v is the derivative correct?

  68. Awstinf
    • 4 years ago
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    yes sir

  69. ChrisV
    • 4 years ago
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    with that i can get the velocity at impact

  70. ChrisV
    • 4 years ago
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    -9.8(5.6)+v=0 v= 54.88

  71. Awstinf
    • 4 years ago
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    yes but you need to know what v initial is

  72. ChrisV
    • 4 years ago
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    well wouldnt that be as simple as making t 0?

  73. Awstinf
    • 4 years ago
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    I dont think you can do that because you are stating that v(5.6)=0

  74. Awstinf
    • 4 years ago
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    Its hard to explain

  75. ChrisV
    • 4 years ago
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    yea i see lol

  76. Awstinf
    • 4 years ago
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    Try reposting this in the physics section, they are really good at explain this kind of stuff

  77. Awstinf
    • 4 years ago
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    http://www.blurtit.com/q3330030.html

  78. ChrisV
    • 4 years ago
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    will do thanks

  79. Awstinf
    • 4 years ago
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    I was right :)

  80. Awstinf
    • 4 years ago
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    the initial velocity is 0

  81. ChrisV
    • 4 years ago
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    :)

  82. ChrisV
    • 4 years ago
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    :)

  83. Awstinf
    • 4 years ago
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    Sorry I was trying to be ambiguous I didnt want to give you improper information

  84. Awstinf
    • 4 years ago
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    I am in your same level class lol

  85. Awstinf
    • 4 years ago
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    I just do about 6 hours of hw a day

  86. ChrisV
    • 4 years ago
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    i took too many courses

  87. ChrisV
    • 4 years ago
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    falling behind

  88. Awstinf
    • 4 years ago
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    yeah it blows I have no social life atm just study study

  89. ChrisV
    • 4 years ago
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    com 101 is more time consuming than i thought

  90. Awstinf
    • 4 years ago
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    :( yeah thats the draw back of underestimating courses. I'm taking physics, chem, physics lab, calc and I really thought this semester would be a tad less stressful

  91. ChrisV
    • 4 years ago
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    chem, com 101, calc and us history

  92. ChrisV
    • 4 years ago
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    history and chem is ok, but com 101 is taking way to much of my time

  93. Awstinf
    • 4 years ago
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    us history=gun to my head i finished all of my gen ed first so I could figure out what I wanna do

  94. ChrisV
    • 4 years ago
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    taking way to much time writing and preparing for speeches

  95. Awstinf
    • 4 years ago
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    Thats why I stick to courses that strictly deal with numbers

  96. Awstinf
    • 4 years ago
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    lol

  97. ChrisV
    • 4 years ago
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    lol its a req for my degree or i would never touch it

  98. Awstinf
    • 4 years ago
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    :( I just wanna take comparitive virology already, all of these courses building up to it are just BS

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